Mathematics: Post your doubts here!

[ZaqZainab]

w_12_qp_43 question 5(b)

compare the old volume and new volume
by the total volume of he cylinder-volume of both the spheres for new

 

[Jelleh Belleh]

you see there are 6 triangles in so yo know are of triangle=1/2*a*b*sinc <----this is for 1 triangle for you multiply by 6
and a and b will be 2.5 and 2.5 as it is a regular hexagon and all triangles inside will be equal side

Ah, got it! I actually thought of this but it faded away from my head. And then I got this idea that there had to be a specific formula to find the area of a hexagon in specific so I was cursing myself for not remembering it or writing it down in class. xD
Thanks alot! ^-^; Sorry for the trouble!

 

[MoatazKotb♥]

http://papers.xtremepapers.com/CIE/Cambridge IGCSE/Mathematics (0580)/0580_w12_qp_43.pdf

Ok first

(5/x) + (6/x+2
5(x+2)+6x=x(x+2)
5x+10+6x=x*x+2x
0=x*x-9x-10

 

[ZaqZainab]

umm I jst a question :/ is may june 2003 paper 4 question 9 coming? or sth like it coming in the exam tomorrow? cz I honestly don't know how to do anything from it :/ so shud I panic orrr??
heres the qp
http://papers.xtremepapers.com/CIE/Cambridge IGCSE/Mathematics (0580)/0580_s03_qp_4.pdf

It is really rare but it can come as this is the part of the syllabus now you should hope for luck and try figuring it out and it is 7 outta 10 not coming

 

[ZaqZainab]

Ah, got it! I actually thought of this but it faded away from my head. And then I got this idea that there had to be a specific formula to find the area of a hexagon in specific so I was cursing myself for not remembering it or writing it down in class. xD
Thanks alot! ^-^; Sorry for the trouble!

Nah no problem if you have got more bring it own ready for Maths

 

[silentkiller97]

w_12_qp_43 question 5(b)

(x)=5 Y(x+2)=6
yx/5 = Y(x+2)/6
substitute Y=1-y in the equation
((1-Y)x)/5 = (Y(x+2))/6
6x-6Yx = 5Yx +10Y
now substitute Y=6/(x+2)
6x - 6*6/(x+2)*x = 5*6/(x+2)*x + 10*6/(x+2)
6x - 36x/(x+2) = 30x/(x+2) + 60/(x+2)
solve it
you will get 6x^2 = 54x +60
divide the whole equ. with 6 and get the right ans.
x^2 - 9x -10 = 0
HOPE THIS WILL HELP YOU
PRAY FOR ME FOR INSHALLAH I WOULD BE GIVING MY EXAM TOMMOROW

 

[Jelleh Belleh]

Nah no problem if you have got more bring it own ready for Maths

Awesome! Same here, more or less, haha. xD Just solving as many questions as I can before bed, mainly mensuration, as I tend to mess up in those as you could tell. xD

 

[silentkiller97]

what is reflex angle??????

take it as mirror angle IF in a triangle ABC they ask find the reflex angle of <b then you will subtract <b with 360 to get the reflex angle.

 

[saifeddin]

It is really rare but it can come as this is the part of the syllabus now you should hope for luck and try figuring it out and it is 7 outta 10 not coming

what is the name of the topic ?

 

[oahmed64]

On the grid, draw the graph of y = g(x) − 10.
does this mean y=x-10 ?

 

[SleppingAddict97]

http://papers.xtremepapers.com/CIE/Cambridge IGCSE/Mathematics (0580)/0580_w12_qp_43.pdf Q10

 

[SleppingAddict97]

On the grid, draw the graph of y = g(x) − 10.
does this mean y=x-10 ?

it means that we will use the formula of g(x) and subtract it by 10

 

[SleppingAddict97]

http://papers.xtremepapers.com/CIE/Cambridge IGCSE/Mathematics (0580)/0580_w12_qp_43.pdf Q4 PART C,D,E Help

 

[Rockzstar]

does anybody have the booklet which was compiled by baaz pathan???

 

[shazmina]

http://papers.xtremepapers.com/CIE/Cambridge IGCSE/Mathematics (0580)/0580_s12_qp_43.pdf could u plz let me knw hw to solve question no 7 part (c)....

 

[silentkiller97]

TRANSFORMATION MATRICES

 

[ZaqZainab]

On the grid, draw the graph of y = g(x) − 10.
does this mean y=x-10 ?

No this means g(x)=y+10

 

[ZaqZainab]

Awesome! Same here, more or less, haha. xD Just solving as many questions as I can before bed, mainly mensuration, as I tend to mess up in those as you could tell. xD

it is he same with me too

 

[Jelleh Belleh]

does anybody have the booklet which was compiled by baaz pathan???

I probably do! Give me a minute..

 

[Rockzstar]

I probably do! Give me a minute..

yeah sure