• We need your support!

    We are currently struggling to cover the operational costs of Xtremepapers, as a result we might have to shut this website down. Please donate if we have helped you and help make a difference in other students' lives!
    Click here to Donate Now (View Announcement)

Mathematics: Post your doubts here!

Messages
646
Reaction score
39
Points
38
That's because you'll write it as cos x = +- (5/8)^1/4
just like for square root, you write +-(square root)...
So you'll have x= cos^-1 ( positive (5/8)^1/4 ) and x=cos^-1 (negative (5/8)^1/4)
This should give you 4 different values of x.
Ohhhhhh! Yup. Thanks a lot mate!
 
Messages
4,162
Reaction score
1,119
Points
173
it is very hard

lg [(3x)^(lg3)] = lg [(4x)^(lg4)]
lg3 x lg3x = lg4 x lg4x
lg3 x (lg3 + lgx) = lg4 x (lg4 + lgx)
(lg3)^2 + lg3lgx = (lg4)^2 + lg4lgx
(lg3)^2 - (lg4)^2 = lg4lgx - lg3lgx
(lg3 - lg4) (lg3 + lg4) = lgx (lg4 - lg3)
-(lg4 -lg3) (lg3 + lg4) = lgx (lg4 - lg3)
-(lg3 + lg4) = lgx
-lg12 = lgx
lg(1/12) = lgx
x = 1/12
thanks a lot May ALLAH bless you and allow u to help others as u just did thanks :)
 
Messages
1,321
Reaction score
490
Points
93
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w11_qp_33.pdf
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w11_ms_33.pdf

Q6ii) How should we find (a+bi)? I made an Argand diagram and so found it from the sketch. But do we have to show any calculations for this ? If yes, then how to calculate a+bi ?

Alice123
MustafaMotani

or anyone ?

sis marking scHeme tells us everything ... :)
Calc w^2 ... find mid point of w and w^2 ...that will be centre of the circle ....
Find |w-w^2| (length of the diameter)
divide it by 2 to get radius ..
now |z - (centre of the circle)| = radius
 
Messages
870
Reaction score
374
Points
73
sis marking scHeme tells us everything ... :)
Calc w^2 ... find mid point of w and w^2 ...that will be centre of the circle ....
Find |w-w^2| (length of the diameter)
divide it by 2 to get radius ..
now |z - (centre of the circle)| = radius
how do we find the mid-point of w and w^2 :(
 
Messages
168
Reaction score
50
Points
38
Any one get this? What mistake have I done? Mark scheme said s=2 but I got 1.4?
 

Attachments

  • IMG-20130517-00078.jpg
    631.6 KB · Views: 10
Messages
1,601
Reaction score
553
Points
123
Any one get this? What mistake have I done? Mark scheme said s=2 but I got 1.4?
you did everything correct except you have to subract x=1+s with -3 as shown in the question (r-3i) which means r has to subtracted from vector (3,0,0) j and k are zero in this case :)
 
Messages
10
Reaction score
1
Points
3
i have a question, the paper its from isnt here on xtremepapers, its june 2002 paper 6, q5,
question is: the digits of number 1223678 can be rearraged to give many different 7 digit umbers. find how many 7-digit diferent numbers can be made if
i) there are no restrictions on the order of digits
ii) the digits 1,3,7 are (in any order) are next to each other
iii) these 7 digit numbers are even.

any help?
 
Messages
681
Reaction score
438
Points
73
sis marking scHeme tells us everything ... :)
Calc w^2 ... find mid point of w and w^2 ...that will be centre of the circle ....
Find |w-w^2| (length of the diameter)
divide it by 2 to get radius ..
now |z - (centre of the circle)| = radius

I got the diameter and radius... I was wondering how would we find out the mid- point and I just understood!! We had to use the coordinate geometry formula for mid-point of the two points! Can't believe I didn't think of that before ! Thank you soo much. May Allah bless you and grant you success in this life and in the Hereafter :)

how do we find the mid-point of w and w^2 :(
 
Messages
4,493
Reaction score
15,418
Points
523
i have a question, the paper its from isnt here on xtremepapers, its june 2002 paper 6, q5,
question is: the digits of number 1223678 can be rearraged to give many different 7 digit umbers. find how many 7-digit diferent numbers can be made if
i) there are no restrictions on the order of digits
ii) the digits 1,3,7 are (in any order) are next to each other
iii) these 7 digit numbers are even.

any help?
i) 7!/2!
ii) consider 1 3 and 7 to be in a box and consider that box to be one dash
_ * 7 *6*5*4*3*2*1

number if dashes 8 and inside the box 3!
so 8!*3! /2! because 2 comes twice thats y we divide

iii) that means they wud end at 2,2,6,8
6! *4 /2!
 
Top