mechanics paper 51

[iKhaled]

anyone did that paper today ? sorry i mean 52!!!

 

[*MK*skydiver :D]

I diiiiiiiid! So someone else in the whole wide world does actually take mechanics 2 ! seriously ,Ooo Em Gee I only know of 4 students taking M2 (me inculded) ,how many do you know ,taking M2 imean?

How was it ? For me , it was decent ,pretty good ;except for the question with the EPE and particle P and object B , rmmbr that ? It asked for the speed of P and for coefficient of friction ,,,

 

[fathimaash]

Ya I sat fr it

 

[*MK*skydiver :D]

Don't discuss answers PM or wait for 24 hrs

 

[iKhaled]

I diiiiiiiid! So someone else in the whole wide world does actually take mechanics 2 ! seriously ,Ooo Em Gee I only know of 4 students taking M2 (me inculded) ,how many do you know ,taking M2 imean?

How was it ? For me , it was decent ,pretty good ;except for the question with the EPE and particle P and object B , rmmbr that ? It asked for the speed of P and for coefficient of friction ,,,

1. finally the forums worked omg!!
2. OMG u r the only one i know now that takes M2 finally i found someone haha everyone is taking S1 like wth -_-

 

[Shreeram]

I took m2 today
It was not bad but expect that the gt would be lower

 

[fathimaash]

Wat ws da answer fr da speed on the pulley qus???

 

[lisaann]

Wat ws da answer fr da speed on the pulley qus???

Was it 1 ?

 

[fathimaash]

Was it 1 ?

No idea wat da correct ans is but I got 6.54. :/

 

[lisaann]

No idea wat da correct ans is but I got 6.54. :/

Emmm
what did you get for q2 ?
the centre of mass of semicircle was 1/3PIE ?
and the angle was 40 or 30 something like dat ?

 

[fathimaash]

Emmm
what did you get for q2 ?
the centre of mass of semicircle was 1/3PIE ?
and the angle was 40 or 30 something like dat ?

It ws 1/6pie.. da qus hd given da diameter not the radius..

 

[fathimaash]

It said da diameter was 0.25m so da radi wil b 0.125 so OG=(2*0.125*sinpie/2) divide by (3pie/2). Which is 0.0530

 

[lisaann]

It said da diameter was 0.25m so da radi wil b 0.125 so OG=(2*0.125*sinpie/2) divide by (3pie/2). Which is 0.0530

Oh!
emm what about the question involving projectiles uy was 9 i guess so the v would be 9/sin40
and the one with the centre of mass of the cone with the weight was it 0.2 something ?
and the integration i guess it was 1.something

 

[fathimaash]

The projectile velocity ws 14 nd the vertical height 0.450 mn..
Yes it 0.22 m fr da cone qus...

 

[fathimaash]

Emmm
what did you get for q2 ?
the centre of mass of semicircle was 1/3PIE ?
and the angle was 40 or 30 something like dat ?

HeY ur ryt.. da radi ws 0.25m..

 

[lisaann]

HeY ur ryt.. da radi ws 0.25m..

Phew..
are u sure though :s ?

 

[fathimaash]

Phew..
are u sure though :s ?

Actually askd 2 friends of mine one says 0.25 nd othr says noo.
Stil in doubt :?

 

[lisaann]

Actually askd 2 friends of mine one says 0.25 nd othr says noo.
Stil in doubt :?

That wont make a big difference anyways.

 

[fathimaash]

That wont make a big difference anyways.

Ikr. But da weight of the lamina was 20N dats confirmed..

 

[lisaann]

Ikr. But da weight of the lamina was 20N dats confirmed..

yeah since you'll have half the value i used on both sides of the equation
6sin45 X r=W X OG