Maths, Addmaths and Statistics: Post your doubts here!

[farhan141]

Can anyone tell me in detail how to find center of rotation?

 

[farhan141]

12^1/2
---------
3^3/2

= 4^1/2
---------
1^3/2

= 2
----
1

= 2

I may be wrong. If someone can correct it then appreciated.

 

[farhan141]

Answer should be 4/9 I guess.

 

[danial 234]

Plz tell me how do we get 2/3 as answer from this |>View attachment 27531

underroot(12/3^3)
underroot(12/9)
underroot(4/3)
2/3

 

[AbbbbY]

12^1/2
---------
3^3/2

= 4^1/2
---------
1^3/2

= 2
----
1

= 2

Uhh you're wrong here.

(12^1/2 ) = underroot 12
3^3/2 = underroot 3*3*3

So, underroot 12 / underoot 27 = underroot (2*2*3) / underroot (3*3*3) = 2 underroot3 / 3 underroot 3. Hence, 2/3

 

[razor1911]

Plz help on this question really don't know the method for it.... from w06 P1 Q8 (c)

Find the smallest positive integer such that 360k is a cube number.

 

[TheStallion-Reborn]

any rule/pattern to follow for those lame nth term questions? or do u have to find reasons and deduce a sensible equation everytime?

 

[Saad Mughal]

any rule/pattern to follow for those lame nth term questions? or do u have to find reasons and deduce a sensible equation everytime?

Here's a great thread, related to the nth term questions.
https://www.xtremepapers.com/community/threads/mathematics.4806/

 

[TheStallion-Reborn]

Here's a great thread, related to the nth term questions.
https://www.xtremepapers.com/community/threads/mathematics.4806/

haaza shukran!

 

[flesh-eater]

http://papers.xtremepapers.com/CIE/Cambridge International O Level/Mathematics D (Calculator Version) (4024)/4024_s10_qp_12.pdf
How do we solve Q23 part a?

 

[AbbbbY]

http://papers.xtremepapers.com/CIE/Cambridge International O Level/Mathematics D (Calculator Version) (4024)/4024_s10_qp_12.pdf
How do we solve Q23 part a?

Dividing it into to right angle triangles,

AX = 16cm

Cos theta= 8/17
And you know the base is 16, so AB = 17*2 = 34

 

[flesh-eater]

Thank you!

 

[Tulaib]

Plz help on this question really don't know the method for it.... from w06 P1 Q8 (c)

Find the smallest positive integer such that 360k is a cube number.

360=(2^3)(3^2)(5),to make it a cube no, all the factors of 360 must be in cubic form, 2 is already in cubic form, so 'k' is (3)(5^2) to make cubes of 3 n 5 as well

 

[Sarah Paul]

If they give a histogram chart. Using the chart how do we find mode and median Can ull please answer this question?

 

[Sarah Paul]

If they give a histogram chart. Using the chart how do we find mode and median Can ull please answer this question?

 

[Snowysangel]

If they give a histogram chart. Using the chart how do we find mode and median Can ull please answer this question?

Find the frequency of each separate x value by the formula f=fd * class width. The value which has the highest frequency is your mode. For medium, you'll have to make a table. You need a CF column..

 

[Snowysangel]

Listen when do we needthe midpoint of each class width. It's only when were drawing a cumulative frequency curve na?

 

[Sarah Paul]

Median is the middle number ryt? Thank You

 

[Sarah Paul]

Median is the middle number ryt? Thank You

 

[razor1911]

360=(2^3)(3^2)(5),to make it a cube no, all the factors of 360 must be in cubic form, 2 is already in cubic form, so 'k' is (3)(5^2) to make cubes of 3 n 5 as well

I understood the part that to make cubic number which 2 is already in cubic form.... But I dont get that part of k (3)(5^2), how r these made into cube numbers and u took 5^2??