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thanx i love u but how did we get 0.1 i didnt get that thanx
The mole ratio of H2O:H2:O2 is 2:2:1. So if H2O loses 0.2 moles, H2 will gain 0.2 and O2 will gain 0.2/2=0.1 moles.
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thanx i love u but how did we get 0.1 i didnt get that thanx
Could you please show the working in detail i knw the methods..1. Construct balanced equations for the combustion of 1 mole (10 cm3) of methane and ethane. Take the moles to be the volume. CO2 will be a product; it'll react with KOH, so you can minus the moles of CO2 from the total volume of the products (i.e. volume of CO2 + H2O).
1. Construct a balanced equation.
1. Construct a balanced equation and use mole ratios.
2. Just take the moles to be the volume. SO2 and CO2 react with NaOH, so you'll minus their volumes from the total volume.
4. Count the electrons!
2. 1 C=C bond will take 1 mole of H2 when it becomes saturated. Count the number of C=C bonds initially, and the number of C=C bonds left after the reaction. Subtract the second from the first to get the number of moles of H2 used.
2. Because NaN3 decomposes to give Na also, which in turn reacts to give more N2. So technically this new N2 is actually coming because of the NaN3. You have to take it into consideration as well.
2. 100 grams of fertiliser contains 15 g of N2. So 14 grams will contain x moles. c=x/v.
HERE YOU GO:
Tell me if you still don't understand; I'll try and make it more clear.
link plscan anyone help with no.6 of M.J 2011 variant 1
also no.11,17,40 of M.J 2011 variant 2.I would be grateful with your help.
link pls
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Chemistry (9701)/9701_w08_qp_1.pdf
Q30
isnt it supposed to be 25 %??
n also Q39 h4rriet Jiyad Ahsan or anyone
thanks
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Chemistry (9701)/9701_w08_qp_1.pdf
Q30
isnt it supposed to be 25 %??
n also Q39 h4rriet Jiyad Ahsan or anyone
thanks
Q 30!
okay here goes, so you know when we find the yield in an ester rxn we use the acid right?
so the mass of the ethanoic acid given is 30, which divided by the mr of the acid
30/60 = 0.5 moles
and in the end the ester formed has mass 22g while its mr is 88, moles of ester formed,
22/88 = 0.25 moles
so if 0.5 moles of acid produces o.25 moles of the ester, we have
(0.25/0.5) x 100 = 50%
hope you got it, dnt mind asking if u didnt.
i'll just do 39 and post it up in a bit
Thanks30. (30+30)-18 (mass of water)=the mass of ester we're supposed to get.
39. The compounds in 1 and 2 are made from C3H7 free radicals. The compound in 3 is made from C2H5 and C4H9 free radicals.
If you know the method, then you should be able to do the working too.Could you please show the working in detail i knw the methods..
Question paper and question number?
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Chemistry (9701)/9701_w08_qp_1.pdf
Q30
isnt it supposed to be 25 %??
n also Q39 h4rriet Jiyad Ahsan or anyone
thanks
bro solve my query pls :/ cannot get it right :/Q39
ok here goes you see the 3 options given right? look closely at the 3rd option.. umm just open the file attached, it should make sense.. if it doesnt all you have to do is ask
k wat abt may june 2006 q10
im on itbro solve my query pls :/ cannot get it right :/
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