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Chemistry: Post your doubts here!

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Check the file,i sent...First findnthe mole of co2.Then using the formula judge the no of mole of the aluminium compound.Then u will get the molar mass by using the mole formula.Finally u will get 144.Try each of the 4 options n u will get c.Hope it helps.
 
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Which process could be used to calculate the bond energy for the covalent bond X-Y by dividing its ∆H by n?
A XYn(g)→X(g) + nY(g)
b 2XYn(g)→2XYn-1(g) + Y2(g)
C Y(g) + XYn-1(g)→XYn(g)
D nXY(g)→nX(g) +n/2 Y2(g)
Why is the answer a?
Help guys.Thanks a lot.
 
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Guys ,just want to ask .For the question below option a is selected is it because it has something to do with the"in situ"preparation.Thanks a lot.
 

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Guys ,just want to ask .For the question below option a is selected is it because it has something to do with the"in situ"preparation.Thanks a lot.

Answer is D as it is reaction between ketone and 24 DNPH, which is able to done without heating :)
 
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Which process could be used to calculate the bond energy for the covalent bond X-Y by dividing its ∆H by n?
A XYn(g)→X(g) + nY(g)
b 2XYn(g)→2XYn-1(g) + Y2(g)
C Y(g) + XYn-1(g)→XYn(g)
D nXY(g)→nX(g) +n/2 Y2(g)
Why is the answer a?
Help guys.Thanks a lot.


Remember what bond energy is,it is the energy released when a covalent bond of a gaseous molecule is broken to give gaseous atoms and not molecules or compounds or molecules. So in A only is this happening in the rest of the options ∆H not only contains the bond breaking energy but also bond formation so the resulting ∆H for B,C and D is lesser than the value of X----Y bond energy !
I hope you get it its pretty simple just try to understand and ask any question no matter how childish it is about this explanation ! :)
 
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Remember what bond energy is,it is the energy released when a covalent bond of a gaseous molecule is broken to give gaseous atoms and not molecules or compounds or molecules. So in A only is this happening in the rest of the options ∆H not only contains the bond breaking energy but also bond formation so the resulting ∆H for B,C and D is lesser than the value of X----Y bond energy !
I hope you get it its pretty simple just try to understand and ask any question no matter how childish it is about this explanation ! :)
Thanks bro.
 
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