Mathematics: Post your doubts here!

[Suchal Riaz]

f = hg
h = f/g = ((x-2)^2 +3)/(x-2), which simplifies to 3/(x-2) + (x-2)

Do tell me If I´m wrong.

\
f,h,g are functions not variables

 

[Namehere]

lol
View attachment 39505
you are a smart girl you can figure out rest of it. it's just one mark question. it will take less than 20 sec to do but i don't have f inverse

I don´t get it. Can you explain please?

 

[Suchal Riaz]

sin is a function. this is what you do always:

 

[Suchal Riaz]

here's a joke

 

[Namehere]

here's a joke

View attachment 39510

not bad to be a maths joke

 

[periyasamy]

yea exactlyy..! that's what i was writing
seee if u can solve this equation :

View attachment 39455

and make it into
View attachment 39456

Hai.I cant get it.I m not sure.The question u just gave me here is it a past year?What year it is?

 

[sumeru]

yea exactlyy..! that's what i was writing
seee if u can solve this equation :

View attachment 39455

and make it into
View attachment 39456

Here it is...

 

[Snowysangel]

lol
View attachment 39505
you are a smart girl you can figure out rest of it. it's just one mark question. it will take less than 20 sec to do but i don't have f inverse

Shouldn't it be h= fg^(-1) since we're changing the position of g(x)?

 

[abruzzi]

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w12_qp_31.pdf
I need some help with qn no. 8(i and ii). Could anyone please help me understand the solutions?
Thanks

I'm re-posting this,. anyone??

 

[sumeru]

I'm re-posting this,. anyone??

 

[usama321]

View attachment 39473
part iii please

Actually it would be done this way. I was also confused about it

f (x) = hg(x)
(x-2)^2 + 3
Now, since hg is a composite function, the value of g, which is x-2, would have to be put into the value of h in such a way that it becomes, (x-2)^2 + 3.

Thus h would be x^2 + 3. You can put in the value of g now and you will get f(x)

 

[Snowysangel]

Actually it would be done this way. I was also confused about it

f (x) = hg(x)
(x-2)^2 + 3
Now, since hg is a composite function, the value of g, which is x-2, would have to be put into the value of h in such a way that it becomes, (x-2)^2 + 3.

Thus h would be x^2 + 3. You can put in the value of g now and you will get f(x)

I don't get it...how is (x-2)^2 + 3 relevant?

 

[usama321]

I don't get it...how is (x-2)^2 + 3 relevant?

f = (x-2) ^2 + 3, and that is what the composite function hg(x) is equal to and as g = x-2, we have to make hg(x) equal to f(x)

h(g)= g^2 +3 = (x-2)^2 + 3 thus our answer is x^2+3

 

[daredevil]

Here it is...

thankkss a lot man!! that was wat i was asking !!

Hai.I cant get it.I m not sure.The question u just gave me here is it a past year?What year it is?

here u go periyasamy

 

[periyasamy]

thankkss a lot man!! that was wat i was asking !!

here u go periyasamy

Thank u a lot.Sorry for the early trouble.

 

[daredevil]

Thank u a lot.Sorry for the early trouble.

no trouble at all

 

[ZaqZainab]

f = hg
h = f/g = ((x-2)^2 +3)/(x-2), which simplifies to 3/(x-2) + (x-2)

Do tell me If I´m wrong.

nope its not this way

 

[Thought blocker]

nope its not this way

I guess, we have to take h=f inverse g, isn't it ?

 

[ZaqZainab]

lol
View attachment 39505
you are a smart girl you can figure out rest of it. it's just one mark question. it will take less than 20 sec to do but i don't have f inverse

I still don't get it
the f inverse is root of(x-3) + 2

 

[386423]

http://papers.xtremepapers.com/CIE/...AS Level/Mathematics (9709)/9709_s09_qp_1.pdf
question 10