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How was the Maths paper 12
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The threshold would be low as the wording of the question were changed
We can prove it as reflex angle is b/w 270-360 which is theta, 2*theta will be equal to 540-720 which lies in 3rd and 4th quadrant where sin is -ive.The only question which actually required thinking would probably be the sin2 theta question. The rest of them required basic concepts.
Yeah I know. I used the first method. Btw, you could get banned for this. It's not been 24 hrs. yet so you can't discuss answers.We can prove it as reflex angle is b/w 270-360 which is theta, 2*theta will be equal to 540-720 which lies in 3rd and 4th quadrant where sin is -ive.
Also sin2 theta = 2sin theta * cos theta, put the values from (i) the ans will be in negative![]()
y= 0.5x 5.5Guys what was the equation of the tangent in the second last question?
0.5833what are the area of shaded region?
It was 10.83Was the y-coordinate of the maximum in the 8-marks question in decimal/fraction or a whole number?
For finding the constant c when differentiating, you did take 3 as x but you mistakenly took 0 instead of -10. It's wrong what you did. We will take the point (3,-10). Why did you take at x=3?It was 10.83
HAHAHAHAHAHAHA! lol It was a double derivative. When you integrate you get the first derivative. For max and min points you need to equate it to 0For finding the constant c when differentiating, you did take 3 as x but you mistakenly took 0 instead of -10. It's wrong what you did. We will take the point (3,-10). Why did you take at x=3?
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