Physics: Post your doubts here!

[Thought blocker]

sorry it was 5 V in the marking scheme i didnt get tht

Okay So you have two Voltages That are 225 and 230 yes ? (Keep 230 as V1 and 225 as V2)
So you need total Voltage in cell would be V = V1-V2 = 5V

 

[Thought blocker]

Then if the data is to 2.s.f then we must leave the ans to 2.s.f.

Do what question says

 

[student1415]

Okay So you have two Voltages That are 225 and 230 yes ? (Keep 230 as V1 and 225 as V2)
So you need total Voltage in cell would be V = V1-V2 = 5V

thank you soo much !! haha tht was simple

 

[Browny]

Do what question says

Some questions the data is to 2.s.f and if we can't state the answer to a greater number than justified then it should be to right?

 

[Asad Moosvi]

http://papers.xtremepapers.com/CIE/...nd AS Level/Physics (9702)/9702_w12_qp_22.pdf

In the first question, the last part, how do we know the time it reaches terminal velocity at?

 

[Browny]

Ah one more thing thought blocker there was a question where the answer was 4.533333333.......*10^-3 the ans in m.s was to 2s.f. that is 4.5*10^-3.

 

[Asad Moosvi]

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_w12_qp_22.pdf

In the first question, the last part, how do we know the time it reaches terminal velocity at?

Anyone??

 

[Thought blocker]

Ah one more thing thought blocker there was a question where the answer was 4.533333333.......*10^-3 the ans in m.s was to 2s.f. that is 4.5*10^-3.

Hm, yeah, so what's the big deal ?

 

[forever_chocoholic]

http://papers.xtremepapers.com/CIE/...and AS Level/Physics (9702)/9702_w02_qp_2.pdf
can someone explain how to solve question 5 (b) please !!!!

 

[_Ahmad]

Anyone??

It reaches terminal velocity after falling about 10m
so we can find how long it takes to fall 10m from the equation s=ut+0.5gt^2
s=10m
ut=0 since initial velocity is zero
g=9.81
therefore t is about 1.43 s
so it reaches terminal velocity(7ms^-1) at about 1.43 s

 

[forever_chocoholic]

http://papers.xtremepapers.com/CIE/...nd AS Level/Physics (9702)/9702_w13_ms_23.pdf
can anyone help me with question 5 c? pleaseeeeeeeeeeee

 

[mehria]

Anyone??

the terminal velocity is given in part c(ii) 1 n the distance is also given so we will simply find the time by any kinematics equation...

 

[Asad Moosvi]

http://papers.xtremepapers.com/CIE/...nd AS Level/Physics (9702)/9702_w12_qp_22.pdf

May someone please explain the last part of question 5? part b.

 

[DeViL gURl B)]

Th

Projectile Motion
Important Equations

Thank you soooooo much!!!!!

 

[Asad Moosvi]

It reaches terminal velocity after falling about 10m
so we can find how long it takes to fall 10m from the equation s=ut+0.5gt^2
s=10m
ut=0 since initial velocity is zero
g=9.81
therefore t is about 1.43 s
so it reaches terminal velocity(7ms^-1) at about 1.43 s

But in the answer it says it has to be between 1.5s and 3.5s.

 

[Asad Moosvi]

the terminal velocity is given in part c(ii) 1 n the distance is also given so we will simply find the time by any kinematics equation...

All I see is a bunch of weird symbols.

 

[Snowysangel]

IS the decay constant in the AS level syllabus ?

 

[omaaaar]

Thought blocker
Could you tell me all the formulas to be used in waves

 

[DeViL gURl B)]

DeViL gURl B) help please

As u move along .. U know u see bright and dark fringes that is exactly what implies Here as well.. The dark fringes go for the minima and light go for the maxima .., in the same manner if u gi with the dots indicated .. U can say that If at O it is bright.. Then go along the dots and as u reach P is is maxima that is bright!
And u can say the readings go from maxima to minima ...and vice verse.
Hope it helps ya

 

[forever_chocoholic]

IS the decay constant in the AS level syllabus ?

no it is not included