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Consider the weight of a column of air of cross-sectional area A and height h stretching from sea level to the edge of the atmosphere.Can anyone help me with this?? "B"View attachment 65228

The density of the air decreases linearly with height above sea level, so the average density of air in the column is ρ/2 where ρ is the density of air at sea level.

The difference in pressure between the bottom and the top of the column of air is P, the atmospheric pressure at sea level.

The weight of the air column is ρgAh/2 and therefore P = ρgh/2

Solve for h