Physics: Post your doubts here!

TheJDOG

TheJDOG

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forever_chocoholic said:
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_w13_ms_23.pdf
can anyone help me with question 5 c? pleaseeeeeeeeeeee

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_w02_qp_2.pdf
AND can someone explain how to solve question 5 (b) please !!!!:(
Click to expand...

Hello for the ripple tank question 5 c,

They asked us to draw and explain, you need to draw the ripple tank and label, you need to show a light source and label it, and draw a screen and also you need to tell them that you use a video camera to observe the waves.



For 5b, if you look at the wave T1, you'll see that 1 Wavelength is 6 blocks.
We know that 1 Wavelength is 360 degrees.
It's given that T2 lags 60 degrees behind.
So we do, 360---> 6 blocks
60-----> ? Blocks

So this means that t2 lags behind t1 by one block.
When you draw t2 it has to have the same Amplitude A as of T1
Superposition principal : When two waves meet, total displacement is the vector sum of the individual displacements of the waves.

If I have any mistakes someone correct me :D Good luck on tomorrow's Physics P2 guys :D
 
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trao11

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umair1161 said:
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s13_qp_22.pdf

Q5 (b) Please!

Thanks in advance! :)
Click to expand...

The nodes are the points with 0 displacement, and antinodes are regions with maximum amplitude :)
For part (ii) you need to see how many wavelengths appear in the length PQ. For PQ, you have 1.5 lamda, and the frequency is 0.80. Hence the distance is 0.80*1.5 = 1.2

I didn't understand part (iii), can someone please help with that? Thank you :)

I hope that answers your question adequately :)
All the best for tomorrow.
 
umair1161

umair1161

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trao11 said:
The wave produced reflects of point Q on the wall. The incident and reflected waves have the same speed and frequency, and interfere at various points across the string. This produces a stationary wave.

I hope that answers your question adequately :)
All the best for tomorrow.
Click to expand...


Im sorry but can you please elaborate please! Please write out a full answer as you would write in the exam!

Thank You :)
 
TheJDOG

TheJDOG

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umair1161 said:
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s13_qp_22.pdf

Q5 (b) Please!

Thanks in advance! :)
Click to expand...
Hello, for Q5 b I,
Anti nodes are the points where there is maximum displacement of the wave, in this case, they're three antinodes.
Nodes are the points where there is zero displacement, in this case, they're 4 nodes, including 2 nodes at P and Q.
For Ii) look at Wave PQ carefully, you'll see that it's 1.5 lambda.
In part a) you already worked out lambda and got that it's 0.8m
So for length of PQ just substitute and you'll get Length= 1.5 x 0.8 = 1.2 m

For part three, look 2 pages back in this thread and you'll see the explanation with an animation.
 
umair1161

umair1161

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TheJDOG said:
Hello, for Q5 b I,
Anti nodes are the points where there is maximum displacement of the wave, in this case, they're three antinodes.
Nodes are the points where there is zero displacement, in this case, they're 4 nodes, including 2 nodes at P and Q.
For Ii) look at Wave PQ carefully, you'll see that it's 1.5 lambda.
In part a) you already worked out lambda and got that it's 0.8m
So for length of PQ just substitute and you'll get Length= 1.5 x 0.8 = 1.2 m

For part three, look 2 pages back in this thread and you'll see the explanation with an animation.
Click to expand...

It is?? Can you please link me the post please! cant find it! :(

Thanks :)
 
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marimin

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trao11 said:
Smaller radius means smaller force, and hence smaller acceleration.
It will be of the same shape, below the original curve :)
Click to expand...
thanks a lot :). I am still confused but. Correct me if i am wrong...doesnt smaller radius means smaller resisting forece...hence smaller deceleration?? and also higher terminal velocity reached....???
 
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