Biology; Chemistry; Physics: Post your doubts here!

[Dark Destination]

D says non-metal and non-metals form negative ions so they can't be in positive ion state.
They can't lose electrons only gain them. To form positive ions they must have lost an electron which does not happen.

No, but Hydrogen has positive ions when it discharges on cathode. That's the problem. D can be Hydrogen.

 

[FLRNAB]

that would be peshawri man

They come from china as well. C4 is only added here by lala.

 

[M.Omar]

So you are saying the voltmeter itself has a potential difference
And the voltage of the voltmeter is the reading of the voltmeter.. which is very close to the EMF of the cell?

Of course since electric potential is expended due to high resistance of voltmeter(P=I *R) it wud register a p.d

 

[FLRNAB]

No, but Hydrogen has positive ions when it discharges on cathode. That's the problem. D can be Hydrogen.

Hydrogen is diatomic.

 

[Dark Destination]

Hydrogen is diatomic.

Yes, but originally one hydrogen ion discharges. Then two hydrogen atoms join to form the diatomic form.

 

[Faizan Muhammmad]

The pivot does not balance the ruler,the moment provided by newton meter equalizes the other moment.Of course the meter exerts a foce but tht force only creates an opposing moment and dose not cancel the weight force of the object as it is not in line with weight..Like I said earlier if it were to be exactly below (i.e in dirct line witht he weight OF THE BLOCK) then it WUD cancel the weight of the block and picvot wud exert 1.2 N coz it needs to oppose weight of scale alone

iss tarah ka sawal paper main na ayay nae to phir wohee A or C walee larai hogee

 

[funky brat]

Can someone explain it to my why the answer is C and not D :/

D main reduction ho rai hai. Anode pe oxidation hoti hai.

 

[Dark Destination]

D main reduction ho rai hai. Anode pe oxidation hoti hai.

D is cathode.
Read the question.

 

[FLRNAB]

The pivot does not balance the ruler,the moment provided by newton meter equalizes the other moment.Of course the meter exerts a foce but tht force only creates an opposing moment and dose not cancel the weight force of the object as it is not in line with weight..Like I said earlier if it were to be exactly below (i.e in dirct line witht he weight OF THE BLOCK) then it WUD cancel the weight of the block and picvot wud exert 1.2 N coz it needs to oppose weight of scale alone

Can you draw a diagram?

The pivot should only exert 1.2 Newtons since Newton meter moment cancels the 4N weight moment.

 

[FLRNAB]

Yes, but originally one hydrogen ion discharges. Then two hydrogen atoms join to form the diatomic form.

And that must be shown by the equation. Which is not the case here.

The equation would be like this if X was diatomic:
2X + 2e- --> X2

 

[M.Omar]

iss tarah ka sawal paper main na ayay nae to phir wohee A or C walee larai hogee

and u said it was relatively easy.

 

[Muhammad_Hamza]

Anyone?

 

[funky brat]

D is cathode.
Read the question.

To cathode pe reduction nahi hoti? -.-

 

[funky brat]

Anyone?

 

[Dark Destination]

To cathode pe reduction nahi hoti? -.-

Lol. Question to parh lo

 

[M.Omar]

Can you draw a diagram?

The pivot should only exert 1.2 Newtons since Newton meter moment cancels the 4N weight moment.

It cancels the moment but NOT the weight..See tht,s the confusing part.
But let me illustrate.
Consider a balanced metre rule on a pivot(50 cm mark) now two weight are added on opp sides of pivot such tht they balance overall.Does the pivot exert no force?
No infact it wud exert force to oppose weight of rule and combined weight of two of thoses weights.Remember only moments are equalized and the weight still acts downwards;there,s to be sth tht opposes their weight as well and tht is pivotal exertion(force

 

[funky brat]

Lol. Question to parh lo

So that non-metal part only makes option D wrong.

 

[Laibaaa]

C is anode which should show oxidation
D is cathode which should show reduction
Lekin dono sahi lag rahe hain. :|

 

[funky brat]

C is anode which should show oxidation
D is cathode which should show reduction
Lekin dono sahi lag rahe hain. :|

Han thek hai lekin cathode pe cations jaen gey. So that makes the last option metal.

 

[Dark Destination]

C is anode which should show oxidation
D is cathode which should show reduction
Lekin dono sahi lag rahe hain. :|

Both are right equations.
But in D, the end product is not a diatomic molecule, H2..