Maths, Addmaths and Statistics: Post your doubts here!

[asadalam]

http://papers.xtremepapers.com/CIE/Cambridge International O Level/Mathematics D (Calculator Version) (4024)/4024_s05_qp_2.pdf
Q-5 a) ii)

Total frequency=25
Half=12.5 which is rounded off to 13 cuz it is halved from an odd number and is in decimals.
Check in which class is the total up to 13. in 0 class it is 8 so thats not median.In 1 class it is 8+5=13 so 1 class includes this middle value and is median

understand?

 

[era30amy]

Total frequency=25
Half=12.5 which is rounded off to 13 cuz it is halved from an odd number and is in decimals.
Check in which class is the total up to 13. in 0 class it is 8 so thats not median.In 1 class it is 8+5=13 so 1 class includes this middle value and is median

understand?

Yo! =p

Thanks.
Give me a similar question. I want to assess myself. :c

 

[asadalam]

Yo! =p

Thanks.
Give me a similar question. I want to assess myself. :c

Im sleepy

 

[era30amy]

Im sleepy

Ask im to sleep and meanwhile you find a question for me.

 

[asadalam]

Ask im to sleep and meanwhile you find a question for me.

 

[FLRNAB]

Im sleepy

How do you find if 2 lines are perpendicular to each other given vectors?

 

[Dark Destination]

How do you find if 2 lines are perpendicular to each other given vectors?

We can't, i think. At this level.
We can know if they are parallel, if their is a fixed ratio between them..

 

[asadalam]

How do you find if 2 lines are perpendicular to each other given vectors?

Product of gradients will be -1 i think...

 

[era30amy]

How do you find if 2 lines are perpendicular to each other given vectors?

Find their gradient?
If it's -1, they are perpendicular. Jees

 

[FLRNAB]

Product of gradients will be -1 i think...

Find their gradient?

Yeah I know that method but how?

 

[asadalam]

We can't, i think. At this level.
We can know if they are parallel, if their is a fixed ratio between them..

We can,it was in an o level q.Expected answer was to find by using pythagoras but product of gradient is -1 in perpendicular lines(some add maths stuff i read) was also expected.

 

[asadalam]

Yeah I know that method but that's not possible in vectors.

Do you have the q?

 

[Dark Destination]

We can,it was in an o level q.Expected answer was to find by using pythagoras but product of gradient is -1 in perpendicular lines(some add maths stuff i read) was also expected.

But that's a method for lines on the Cartesian plane. He is talking about vectors.

 

[FLRNAB]

Find their gradient?
If it's -1, they are perpendicular. Jees

Jees how to find the gradient genius?

 

[asadalam]

But that's a method for lines on the Cartesian plane. He is talking about vectors.

Oh sorry,neend bohat ayi hoi hai....

Jees how to find the gradient genius?

Do you have the question?

 

[FLRNAB]

Do you have the q?

No I saw they always ask about paralel vectors and if they say perpendicular I should know that.

 

[Dark Destination]

Jees how to find the gradient genius?

You can suppose the first point to be (0,0) and add the column vector to this, to get the next point. Then use those two points to find gradient.
Then do the same for the other vector.
If the product of gradients is -1, they are perpendicular.

 

[asadalam]

You can suppose the first point to be (0,0) and add the column vector to this, to get the next point. Then use those two points to find gradient.
Then do the same for the other vector.
If the product of gradients is -1, they are perpendicular.

I was thinking the same thing,but i though what to do if they give vectors like 3a or 2b....if vector in column is given we can find.

 

[Dark Destination]

I was thinking the same thing,but i though what to do if they give vectors like 3a or 2b....if vector in column is given we can find.

Proving perpendicularity of vectors is not even in our syllabus.

 

[FLRNAB]

Proving perpendicularity of vectors is not even in our syllabus.

That salt in chem atp wasn't in our syllabus. !