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i meant moles of ethanol and ethanoic acid
Sn is oxidised from2+ to 4+ so change in oxidation number=+2http://papers.xtremepapers.com/CIE/... AS Level/Chemistry (9701)/9701_s13_qp_11.pdf Q11 ansB Q20 ansB Q30 ansB
but i was talking about the water and ethyl ethanoate... it means when there is no units we can take 1?i meant moles of ethanol and ethanoic acid
yup so why did you take 1 mole of H20?i meant moles of ethanol and ethanoic acid
if rate in unaffected by concentration of OH it means that the slow step doesn't involve OH. it means it is Sn1 reaction. so the bromine is on a teriary carbon.so D is the answer.Q26) When an isomer Y of molecular formula C4H9Br undergoes hydrolysis in aqueous alkali to form
an alcohol C4H9OH, the rate of reaction is found to be unaffected by changes in the concentration
of OH– ions present.
Which is the most likely molecular structure of Y?
A CH3CH2CH2CH2Br
B CH3CH2CHBrCH3
C (CH3)2CHCH2Br
D (CH3)3CBr
Pls solve dis
the moles of water are not = 1but i was talking about the water and ethyl ethanoate... it means when there is no units we can take 1?
OH F**K i wrote 1 instead of x sorry.View attachment 45161
here i did a little editing i hope suchal doesn't mind
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Chemistry (9701)/9701_w11_qp_11.pdf
Q4(C),17(C),20(C),27(D),35(B),36(A)
telling to whom bro?i solved it on the paper and then copied on the mspaint but i made a typo. sorry
Also i dont get Qs 11 and 23 in this ppr http://papers.xtremepapers.com/CIE/... AS Level/Chemistry (9701)/9701_s12_qp_13.pdfIn statement 1, 2 moles of ethanoic acid will react with 1 mole of calcium ion as charge on calcium is +2. So compound will be Ca(CH3CO2)2 which has empirical formula CaC4H6O4.
In 2 and 3, both H from CO2H will be removed so empirical formula will be CaC4H4O4 and not CaC4H6O4.
How CH●? If you remove from the methyl groups they will be same but not CH.The answer would be C we can have CH3●
we can have CH3CH2●
or just CH●
hey for how long u will b available today cuz i might hve some more questions nd u know tomorow is pprIn statement 1, 2 moles of ethanoic acid will react with 1 mole of calcium ion as charge on calcium is +2. So compound will be Ca(CH3CO2)2 which has empirical formula CaC4H6O4.
In 2 and 3, both H from CO2H will be removed so empirical formula will be CaC4H4O4 and not CaC4H6O4.
C● ehhh sorryHow CH●? If you remove from the methyl groups they will be same but not CH.
Also i dont get Qs 11 and 23 in this ppr http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Chemistry (9701)/9701_s12_qp_13.pdf
1 mole=24 dm^-1
x moles= 0.3 dm^-1 (volume of O2)
This way we will get the moles of oxygen: 0.0125 mol
Then using the mass of each element we find the moles of that particular element using the formula moles=mass÷molecular mass. Then we form equations of the reaction of each element with oxygen:
Ca + 0.5 O2 -> CaO
Mg +0.5 O2 -> MgO
2K + 0.5 O2 -> K2O
2Na + 0.5 O2 -> Na2O
Since we already have the moles of each element, we can now find the moles of oxygen each element requires and that should be equal to 0.0125.
In this case 0.05 moles of sodium gives us 0.0125 moles of O2. Hence the answer D.
11: A: x mol of R, 2 mol of Q so total 3x of products. P is initially x so as 1 mole of P it will be 2-x. Total are 2+2xAlso i dont get Qs 11 and 23 in this ppr http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Chemistry (9701)/9701_s12_qp_13.pdf
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