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Chemistry: Post your doubts here!

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THE ANS IS B FOR Q11! BUT u did The Correct Method :)!
Hi, please include answers to the questions so its easier to reply.

s12qp13

Q11. Unless you can do them mentally, it might be advisable to adopt a trial and error approach to this question.
Go from options A to D and see which one gives you the correct total moles of gases in the end

I will use D as example as its the answer.

View attachment 45167

Q23. Draw all possible structural isomers of C4H8O2 that has ester bonds.

E.g CH3CH2COOCH3, CH3COOCH2CH2CH3, etc...
 
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question number 1:
NH4+: each Hydrogen has +1 oxidation number.total +ve oxidation number by H =4. overall charge is +1.
4-1= 3
N must have -3 oxidation number.
NO3-:each oxygen:-2, all oxygen:-6 overall:-1, -1-(-6)=+5
N2O: oxygen:-2, overall=0; 0-2=+1
change of N of NH4= =+1--3=4
change of N of NO3=+1-5=-4​
22:
B and C not possible. `A` will give many chloropronanes so yeild of 2 chloropropane will be low.​
 
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w11qp11

Q4. There is 1 lone pair on the N atom. So we have 2 bond pairs and 1 lone pair, which is sightly below 120 degrees.

Q17. Volatility has to do with intermolecular attraction. As electrons/protons increases, the instantaneous dipole- induced dipole gets stronger.

Q20. Cold dilute Mno4 adds 2 OH across the double bond. Hot MnO4 cleaves the double bond, and there are 2 6-member rings left.

Q27. CH3CH2CH2CH3
Replacing any the 6 red H gives us 1-chloropropane
Replacing any of the 4 white H gives us 2-chloropropane.
So by probability, we have 6:4 which is 3:2

Q35:
Cl- --> HCl (no redox)
Br- --> HBr --> Br2 (oxidised)
I- --> HI --> I2 (oxidised)

Q36.
X is N2 (alkaline hydride is NH3)
Y is NO (diatomic)
Z is NO2 (polar)

Sir can you please elaborate Q20
 
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question number 1:
NH4+: each Hydrogen has +1 oxidation number.total +ve oxidation number by H =4. overall charge is +1.
4-1= 3
N must have -3 oxidation number.
NO3-:each oxygen:-2, all oxygen:-6 overall:-1, -1-(-6)=+5
N2O: oxygen:-2, overall=0; 0-2=+1
change of N of NH4= =+1--3=4
change of N of NO3=+1-5=-4​
22:
B and C not possible. `A` will give many chloropronanes so yeild of 2 chloropropane will be low.​
so we take them separately i didnt know that and i am going for the exam tomorrow :( thanks :D
 
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11: A: x mol of R, 2 mol of Q so total 3x of products. P is initially x so as 1 mole of P it will be 2-x. Total are 2+2x
B: x mol of R, 2 mol of Q so 2x. P is 2-2x as 2 moles of P. Total are 2+x
C: x mol of both R and Q and P is again 2-2x so total 2 moles.
D: x mol of R, 0.5 mol of Q, P is 2-x as x will be halved here as R is 2 moles. Total 2+0.5x

23: Two with acid Methanoic, one with ethanoic, one with propanoic.
Two with methanoic acid as one straight chain and the other with methyl group.
but the answer to question 23 is c tht is 4 esters
 
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w13qp13

Q1.
N in NH4+ is -3, increases by 4 units to from +1 in N2O
N in NO3- is +5, decreases by 4 units to from +1 in N2O

Q22.
A. Is not good as we might get multi substitutions
B. Is not good as we get dichloropropane
C. Cl- will not replace OH
D. Cl will replace at the OH position

Q30.
A. CH2-CH2-CCl2-CCl2-CH2-
Coloured are the repeating units that come from the monomers

Q33. Lower pH means higher conc of H+, due to more H+ released. Which statements are you confused about?

Q37. Which statement are you unsure of?
Statement 3: No COOH group to react with sodium carbonate
 
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if 1,1 dichloroethene polymerise the repeat unit will be -CF2-CH2-
if two repeat units combine the other way around it can be -CF2-CH2-CH2-CF2- of -CH2-CF2-CF2-CH2-
it can't be -CH2-CH2-CH2-CF2(pink color shows wrong group)
only the correct answer follows this pattern:
– CH2 –
CH2 – CCl 2 CCl 2 – CH2 – CH2 –
 
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22D>>This is direct from the book. The reaction with PCl5 is at room temperature,so this will give us the best yield
33D>>Its my doubt too :p
37B>>
1 Tollens’ reagent and a solution containing acidified dichromate(VI) ions --> It will react with this cuz its aldehyde
2 aqueous bromine and Fehling’s reagent -->Since its an aldehyde,it will react with Fehlings reaagent and as it contains double bond,it will react with Br2
3 2,4-dinitrophenylhydrazine reagent and sodium carbonate-->It will react with 2,4-DNPH , But it cannot react with sodium carmonate as there is no -COOH

Hope it helps :)

http://papers.xtremepapers.com/CIE/... AS Level/Chemistry (9701)/9701_w13_qp_13.pdf
 
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if 1,1 dichloroethene polymerise the repeat unit will be -CF2-CH2-
if two repeat units combine the other way around it can be -CF2-CH2-CH2-CF2- of -CH2-CF2-CF2-CH2-
it can't be -CH2-CH2-CH2-CF2(pink color shows wrong group)
only the correct answer follows this pattern:
– CH2 –
CH2 – CCl 2 CCl 2 – CH2 – CH2 –
U mean CCl2 ??! Suchal Riaz
 
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