Mathematics: Post your doubts here!

[MarcoReus]

Thought blocker, answer it rather than liking it.

 

[Thought blocker]

If you haven't done Add Maths - how difficult is A Level Maths? Should I do Add.Maths before I start studying A Level Maths?

Lol I just did IGCSE 0580 math CORE! Yet I am master in Math now, no matter I got E in one month preparation. But I know all things by now. The thing matter here in Math is PRACTICE which I could not do in one month time. Anyways. All the best.

 

[Thought blocker]

Thought blocker, answer it rather than liking it.

My net is not fast as yours. Sorry for the delay of a minute. ._.

 

[ZaqZainab]

If you haven't done Add Maths - how difficult is A Level Maths? Should I do Add.Maths before I start studying A Level Maths?

I did'nt do Add maths and yet i find A level maths quite easy it all depends on how much progress you make every day, however you cant just gulp up everything in some time.

 

[MarcoReus]

I did'nt do Add maths and yet i find A level maths quite easy it all depends on how much progress you make every day, however you cant just gulp up everything in some time.

Cool.

Can I apply the same to Further Maths if anyone here has done it?

 

[ZaqZainab]

Cool.

Can I apply the same to Further Maths if anyone here has done it?

I haven't taken Further maths though but i think if you are good with number it will be easy for you.

 

[Thought blocker]

Cool.

Can I apply the same to Further Maths if anyone here has done it?

All you have to do is pay concentration on your work, do it with all grace in you. It was easy for her, coz she practiced everyday. Now we too have too do to get A!

 

[skittle_geek]

can anyone solve QN 11(ii) (9709 s03 2004)

 

[Thought blocker]

can anyone solve QN 11(ii) (9709 s03 2004)

 

[emma914]

Can anyone solve QN 10(ii)(9709 s03 2005)

 

[emma914]

Can anyone solve QN 7(i),(ii) (9709 w03 2006)

 

[emma914]

HELLLLLLPPPPPPPPPPP
Can anyone solve QN 7 (9709 w06 qp3)

 

[Eyunice]

Help pls. Urgent (

 

[Thought blocker]

Can anyone solve QN 10(ii)(9709 s03 2005)

10ii)
You know that one of the points on line l is 4i -2j +2k
Let this point be X.
Find the direction vector of AX
AX =(4 -2 2) -(2 2 1) =(2 -4 1)
As both A and X lie on the plane the normal of the plane is also normal to this direction vector.
You already know the direction vector of line l.
find the cross product of these two direction vectors to find the normal of the plane.
(2 -4 1) x (1 2 1)
=-6i -j +8k
Now,
r.n = a.n
(x y z). (-6 -1 8) = (-6 -1 8) (2 2 1)
-6x -y +8z =-6
or
6x + y -8z =6.

 

[Thought blocker]

Can anyone solve QN 7(i),(ii) (9709 w03 2006)

HELLLLLLPPPPPPPPPPP
Can anyone solve QN 7 (9709 w06 qp3)

Both link are same.
If your vector is weak here (ch:7) is the solution to make it powerful.
All the best.
If you still do not get the answers. Surely ask me anytime.

 

[Thought blocker]

Help pls. Urgent (

This is a math thread.
Here is a biology thread.

 

[Eyunice]

This is a math thread.
Here is a biology thread.

can you explain?

 

[shinnyyy]

Whats the formula of calculating the distance b/w 2 planes ? ? can anyone explain me plz ..
(topic : Vectors P3 )

 

[Thought blocker]

can you explain?

Hello again. Don't be sad.
ZaqZainab help her in statistics. (Yet haven't start S1)
Well here is that vector answer :¬
8)
i)
Angle ABC is not an angle between three vectors.
It is angle between two vectors: BA and BC

BA = OA - OB = (2i + 3j + 5k) - (4i + 2j + 3k) = -2i + j + 2k
BC = OC - OB = (10i + 6k) - (4i +2j + 3k) = 6i + 2j + 3k

To find angle between vectors, we use dot product:
BA • BC = ||BA|| ||BC|| cosθ
(-2i + j + 2k) • (6i +2j + 3k) = √(4+1+4) √(36+4+9) cosθ
-12+2+6 = 3 x 7 x cosθ
-4/27 = cosθ
θ = 98.5°

ii)
I am not sure of this. Tell me its answer.

 

[Thought blocker]

Whats the formula of calculating the distance b/w 2 planes ? ? can anyone explain me plz ..
(topic : Vectors P3 )

http://www.examsolutions.net/maths-revision/syllabuses/CIE/period-1/P3/module.php
Here, he covers all thing you wanna know or one should know for MAth!
Ch 7 : Vectors.