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Mathematics: Post your doubts here!

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Not much with it! Saved answer here :¬
complex-png.21999

As the question states that the argument of z is least, z must represent the lowest possible point in the shaded region. Draw a tangent from the center to the lowest point on the circle (this doesn't have to be accurate) as shown by the blue line. This line represents |z|. The angle between the radius and the tangent is always 90 so a right-angled triangle is formed. The opposite side, with is equal to the radius is 1 unit. The magnitude of complex u is the hypotenuse and the adjacent represents |z|. you can easily find |u|, √(2^2+2^) = √8.
So, |z| =√(√8)^2 -1^2 = √8-1 =√7

thank you very much for ur explanations ~
 
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If you haven't done Add Maths - how difficult is A Level Maths? Should I do Add.Maths before I start studying A Level Maths?
Lol I just did IGCSE 0580 math CORE! Yet I am master in Math now, no matter I got E in one month preparation. But I know all things by now. The thing matter here in Math is PRACTICE which I could not do in one month time. :( Anyways. All the best. :)
 
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Help pls. Urgent :((
 

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Can anyone solve QN 10(ii)(9709 s03 2005)
10ii)
You know that one of the points on line l is 4i -2j +2k
Let this point be X.
Find the direction vector of AX
AX =(4 -2 2) -(2 2 1) =(2 -4 1)
As both A and X lie on the plane the normal of the plane is also normal to this direction vector.
You already know the direction vector of line l.
find the cross product of these two direction vectors to find the normal of the plane.
(2 -4 1) x (1 2 1)
=-6i -j +8k
Now,
r.n = a.n
(x y z). (-6 -1 8) = (-6 -1 8) (2 2 1)
-6x -y +8z =-6
or
6x + y -8z =6.
 
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Whats the formula of calculating the distance b/w 2 planes ? ? can anyone explain me plz ..
(topic : Vectors P3 )
 
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