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[Anum96]

X^3 − x +6√3 = 0 Help :'(?

 

[Shujaat Khan]

You can do this by iterative formula but I think it is not the best method. Is that the full question in itself? just asking for X^3 − x +6√3 = 0?
You can go polynomial but I don't know how to get f(x)=0 in this case( there's formula beyond A level scope though you could use)

 

[Anum96]

You can do this by iterative formula but I think it is not the best method. Is that the full question in itself? just asking for X^3 − x +6√3 = 0?
You can go polynomial but I don't know how to get f(x)=0 in this case( there's formula beyond A level scope though you could use)

This is the whole question

 

[Shujaat Khan]

View attachment 57248
This is the whole question

Give full question next time you ask something, this is easy use Marking Scheme when you dont know something

Use the form in part (ii) and you get 2values of pheta( reject the other 4 you "normally" get. I believe you get 6values in total right?)
Then replace these 2 values of pheta in equation x=2sin pheta/3^0.5 (the equation in (ii)

 

[Anum96]

Give full question next time you ask something, this is easy use Marking Scheme when you dont know something

Use the form in part (ii) and you get 2values of pheta( reject the other 4 you "normally" get. I believe you get 6values in total right?)
Then replace these 2 values of pheta in equation x=2sin pheta/3^0.5 (the equation in (ii)

oh I feel dumb. Thanks.