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both a and b?PLEASE HELP!
i am sure, a would be done by you, if not then temme..PLEASE HELP!
THANK YOU SO MUCH!i am sure, a would be done by you, if not then temme..
here is b)
For the one triangle BXC :
The area of segment formula u found out in a(ii) use that to find the area of segment BC with r = 4 and alpha = pi/6 = 8pi/3 - 4sqrt(3)
The area of triangle BXC = {1/2 * 2 * 2sqrt(3)/3 } * 2 = 4sqrt(3)/3
The shaded region BXC = area of triangle BXC - Area of segment BC = 16sqrt(3)/3 - 8pi/3
The shaded area BXC = shaded area AXC = shaded area AXB
Therefore total shaded area = 3 * shahded region BXC = 16sqrt(3) - 8pi
225?View attachment 61241 Can anyone help me with question 6) please?
Yep225?
answers?View attachment 61245
Help please
I can't seem to find answer to part i and so I can't do the second part either :/
They're not givenanswers?
let me ask on fb, i got answers, but aint sure.They're not givenIt's from a worksheet paper
uh-lalala!! xD My answers were correctThey're not givenIt's from a worksheet paper
Thankyouuu sooo much!uh-lalala!! xD My answers were correct*I still remmember this stuffs*
https://www.facebook.com/photo.php?fbid=1804591316429599&set=gm.905399119594630&type=3
Click above link.
Anytime.Thankyouuu sooo much!
exact value of tan π/6 is √3/3Can you explain why √3/3
I'm stuck on that part
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