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Mathematics: Post your doubts here!

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can someone tell me how to solve this question


they ask for the range -90<x<90

and they ask to solve sin(x)+sin(180-x)=1/2

what laws and theories do i need to know apart from the quadrant rule and the trigonometry identity ?
 
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can someone tell me how to solve this question


they ask for the range -90<x<90

and they ask to solve sin(x)+sin(180-x)=1/2

what laws and theories do i need to know apart from the quadrant rule and the trigonometry identity ?
Can u post the picture of that question? I am not able to understand else link would work else just a paper varient and year with season.
 
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can someone tell me how to solve this question


they ask for the range -90<x<90

and they ask to solve sin(x)+sin(180-x)=1/2

what laws and theories do i need to know apart from the quadrant rule and the trigonometry identity ?
We just have to solve for x right?
 
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Hi people!
I need help on these questions, only managed to complete question 3b and 3c, any help will be greatly appreciated!
Thanks in advance!
 

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Hi people!
I need help on these questions, only managed to complete question 3b and 3c, any help will be greatly appreciated!
Thanks in advance!
This isnt from 9709 course. Which board is it?
I may give them a try if you can provide answers of it.
 
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All doubts except 9b) are here : https://drive.google.com/open?id=0B3NebwGVUDjGV0pXRUUwcVcxSFU
9b)
For the one triangle BXC :
The area of segment formula u found out in a(ii) use that to find the area of segment BC with r = 4 and alpha = pi/6 = 8pi/3 - 4sqrt(3)
The area of triangle BXC = {1/2 * 2 * 2sqrt(3)/3 } * 2 = 4sqrt(3)/3
The shaded region BXC = area of triangle BXC - Area of segment BC = 16sqrt(3)/3 - 8pi/3

The shaded area BXC = shaded area AXC = shaded area AXB

Therefore total shaded area = 3 * shahded region BXC = 16sqrt(3) - 8pi
madridtas_CR7 Here are the solution you asked me for march 2016 paper 12 question 1(a)(ii) and question 9.
 
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