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Physics: Post your doubts here!

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can anyone please explain this?View attachment 62515
we first need to find the voltage in the external resistance. so using v=ir
hence v=5.5v. since the all of the components are parallel to each other they all have an terminal potential difference of 5.5v
current going into the junction= output of junction.
so the current going into the internal resistance is 0.25A. 0.5/2 as both components have the same p.d and internal resistance they both have the same current
simply then use the formual
terminal p.d=Emf-Ir
5.5=6-0.25r
hence r is 2 ohms
 
Messages
36
Reaction score
19
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8
we first need to find the voltage in the external resistance. so using v=ir
hence v=5.5v. since the all of the components are parallel to each other they all have an terminal potential difference of 5.5v
current going into the junction= output of junction.
so the current going into the internal resistance is 0.25A. 0.5/2 as both components have the same p.d and internal resistance they both have the same current
simply then use the formual
terminal p.d=Emf-Ir
5.5=6-0.25r
hence r is 2 ohms
Thanks
 
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