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2x^2 - 2x > 9
2x^2 - 2x - 9 > 0
Solve this. And suppose u got solme value a and b where b < a then ur final answer will be x > a and x < b
2x^2 - 2x - 9 > 0
Solve this. And suppose u got solme value a and b where b < a then ur final answer will be x > a and x < b
Anyone there to help me I’m kinda stuck in this ques that says
A curve has equation y=2x^2-2x
Find the set of values of x for which y >9
It’s from 9709/12/nov/dec/13