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Recent content by sj0007

  1. sj0007

    .... And this is your life!

    .... And this is your life!
  2. sj0007

    One day you're 17 and planning for someday. Then quietly, without you ever really noticing...

    One day you're 17 and planning for someday. Then quietly, without you ever really noticing, someday is today and that someday is yesterday..
  3. sj0007

    Mathematics: Post your doubts here!

    Yeah you can say so, more like on an educated guess though :P
  4. sj0007

    Mathematics: Post your doubts here!

    Weight is a random variable and that too a continuous one. The distribution for a continuous random variable is 'normal distribution' (according to what we have studied) with parameters (Mean, variance)........ Just put in some sensible appropriate values for an average of weight of 18 year old...
  5. sj0007

    PHYSICS M/J/9702 2017 Paper 41

    An A*, InShaaAllah You?
  6. sj0007

    PHYSICS M/J/9702 2017 Paper 41

    I said kinetic energy = qV And since v=p/m, KE = p^2/2m and then I just rearranged the whole thing
  7. sj0007

    PHYSICS M/J/9702 2017 Paper 41

    Hehe :cool: I didnt really get the chance to talk to many people but everyone I talked to were confused. For them, it was somewhere in the middle, not too good not too bad :D It was like it's either all right or either all wrong :)
  8. sj0007

    PHYSICS M/J/9702 2017 Paper 41

    My grade or the gt?
  9. sj0007

    PHYSICS M/J/9702 2017 Paper 41

    Hahahaha yeah I guess I am XD :cool: But thanks! :p Awww thanks!!! I am glad tooo!!
  10. sj0007

    PHYSICS M/J/9702 2017 Paper 41

    Was it really that hard? I didn't find it that hard :whistle:
  11. sj0007

    Physics: Post your doubts here!

    Use the fact that <c^2> is directly proportional to the kelvin temperature Cross multiply: 1.9 x 10^6 ------------> (32+273) ? -------------> (80+273) Once you get the mean square speed at 80 (that is, '?'), square root it to get root mean square speed
  12. sj0007

    Physics: Post your doubts here!

    They have already provided you with the electric field strength and the charge and are asking you what the additional charge should be to have the electric field strength as 2x10^6 We know that E=kq/(r^2) so we can use the given information to get a value for k/(r^2) since these values will...
  13. sj0007

    Physics: Post your doubts here!

    It's always connected in parallel :)
  14. sj0007

    XPC BEST MEMORY

    haha yeah I got that, I didn't get that YOU were the fish :P
  15. sj0007

    XPC BEST MEMORY

    Okay I confess that I did not get that (the thing about you being the fish) :P and I did get a bit confused at your cheering st first but then I was like, meh, it's probably a figure of speech and yeah you just added a yaaaaaaaayyy :D :cool: Haha, that's very reassuring to be honest <3
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