PHYSICS M/J/9702 2017 Paper 41

[AvgStudent]

My grade or the gt?

Your grade?

 

[sj0007]

Your grade?

An A*, InShaaAllah
You?

 

[Munib Ahmed]

what was the answer for the rms values and for the acceleration in the electric field question

 

[AvgStudent]

i got 4.3 x10^4 and 5.3 x 10^4 for rms and acceleration got like 4 point something to the power 27

yeah i got something similar for rms i think. What did you use to calculate acceleration?

 

[Munib Ahmed]

i got 4.3 x10^4 and 5.3 x 10^4 for rms and acceleration got like 4 point something to the power 27

i got 1370 and 1670 for rms lol

 

[Munib Ahmed]

used colounbs law then F=ma where m was 2u

yep i did tht and got a really big answer hope its correct. did u do the derivation of p=(2mqV)^0.5

 

[Munib Ahmed]

yea it is correct makes sense if

its a big value cause they tend to have bug accelerations yea i did that using 0.5mv^2 and Vq

ya and then we had to multiply both sides by m right. thts what i did lol. and y was the shm question 6 marks what did we have to explain

 

[AvgStudent]

ya and then we had to multiply both sides by m right. thts what i did lol. and y was the shm question 6 marks what did we have to explain

Explain? Wasn't the 6 mark a calculation question?

 

[Munib Ahmed]

Explain? Wasn't the 6 mark a calculation question?

yes it was but the calculation was only 2 steps and it said to explain the answer

 

[Munib Ahmed]

yea you multiply by m i guess you just had to state formulas of omega and the energy and i think it had to be detailed

lol idk i even explained y the oscillations decrease which i think was totally irrelevant. btw in the light intensity question, the light intensity had to be lower right in order for the lamp to light

 

[AvgStudent]

lol idk i even explained y the oscillations decrease which i think was totally irrelevant. btw in the light intensity question, the light intensity had to be lower right in order for the lamp to light

Yes it had to be lower so more resistance of LDR ,more p.d across LDR and hence less p.d across the inverting input. So non-inverting is greater than inverting and output will be positive so diode will allow current to pass to relay.

 

[Munib Ahmed]

yea exactly that

got it right

 

[AvgStudent]

in that electronics question, what did you write for the 2 boxes?

 

[Munib Ahmed]

in that electronics question, what did you write for the 2 boxes?

what boxes

 

[AvgStudent]

what boxes

in the question before the attenuation one, where you had a microphone connected to a speaker with electronics inbetween.
It had an ADC and a series to parallel converter.

 

[Ahmed Medhat]

Hey what was the ratio of input power to noise, and in the very last question what is the energy released in a fission reaction converted to?

 

[AvgStudent]

Hey what was the ratio of input power to noise, and in the very last question what is the energy released in a fission reaction converted to?

I think it was 44 or something. I said kinetic energy of products and as e.m radiation as gamma photons. What did you write?

 

[AvgStudent]

What did you guys do for the very first question about how something stays in orbit?

 

[Ahmed Medhat]

Centripetal force is provided by gravitational force, the centripetal force accelerates the object towards the center and so it is kept in circulat motion, for the very last question the energy releases is in the form of kinetic energy, but the question is about what the energy released is CONVERTED to, not what form it takes.

 

[AvgStudent]

Centripetal force is provided by gravitational force, the centripetal force accelerates the object towards the center and so it is kept in circulat motion, for the very last question the energy releases is in the form of kinetic energy, but the question is about what the energy released is CONVERTED to, not what form it takes.

So what was your answer for that question?