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Recent content by sweet.sugar

  1. sweet.sugar

    Chemistry: Post your doubts here!

    http://papers.xtremepapers.com/CIE/Cambridge%20International%20A%20and%20AS%20Level/Chemistry%20(9701)/9701_s09_qp_1.pdf Q1-D and Q3-C
  2. sweet.sugar

    Chemistry: Post your doubts here!

    http://papers.xtremepapers.com/CIE/Cambridge%20International%20A%20and%20AS%20Level/Chemistry%20(9701)/9701_s09_qp_1.pdf Q1-D and q3-C Plz help
  3. sweet.sugar

    Chemistry: Post your doubts here!

    http://papers.xtremepapers.com/CIE/Cambridge%20International%20A%20and%20AS%20Level/Chemistry%20(9701)/9701_s12_qp_12.pdf Q6-c ( i got D 21.6 i did the calculation twice got 0.06 mol 7dm^3 and temp 303 n calcultaed it using them ) Q20-c (plz write the calculation) Q24-A ( octene ha c8h18 so wen...
  4. sweet.sugar

    Chemistry: Post your doubts here!

    http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Chemistry (9701)/9701_s11_qp_12.pdf Q28(C) Q29-(D) explain plzz :cry:
  5. sweet.sugar

    Chemistry: Post your doubts here!

    That helped,thanks for the effort :)
  6. sweet.sugar

    Chemistry: Post your doubts here!

    http://papers.xtremepapers.com/CIE/Cambridge%20International%20A%20and%20AS%20Level/Chemistry%20(9701)/9701_s11_qp_12.pdf Q8-C Q10-C Q11-C Q19-A Plz help :)
  7. sweet.sugar

    Chemistry: Post your doubts here!

    Look they said which one of them dsnt have lone pairs left So has 5 electrons ryt, 3 will bond with H and since there are 2Na and 2 electrons are left each na would take one Im nt sure though. Hope it made sense :D
  8. sweet.sugar

    Chemistry: Post your doubts here!

    http://papers.xtremepapers.com/CIE/Cambridge%20International%20A%20and%20AS%20Level/Chemistry%20(9701)/9701_s08_qp_1.pdf Q7-D Q10-C Q15-B Q-26-C Q-29-D (how is D chiral :/ ) Q30-C Q33-C ( bt catalysts do increase the kinetic energy of reactants ryt :( ) Thanks.
  9. sweet.sugar

    Chemistry: Post your doubts here!

    Q10 Initial moles of N2O4 as 1 and that of NO2 as zero. 50% of N2O4 dissociates means that 1 moles of NO2 is formed. So total number of moles = 1.5 PArtial pressure of N2O4 = 0.5/1.5 = 1/3 Partial pressure of NO2= 1/1.5 = 2/3 So Kp = (2/3)^2 divided by (1/3). So 4/3 is the answer.
  10. sweet.sugar

    Chemistry: Post your doubts here!

    Haha np bt they said lead(ii)oxide which is PbO :D
  11. sweet.sugar

    Chemistry: Post your doubts here!

    Besides im impressed by the explantion of q1 cz there is no suh thing pno3 n i managed to get the ans by myself we divides 27 by 2 n ans is 13.5 cz o2 molecule has a 2 so tht would be something lile 13.5 * 2 = 27 :) Thx anyway
  12. sweet.sugar

    Chemistry: Post your doubts here!

    Yeah thanks tht helped Bt a small doubt for q-12 u said for sulphur only 1 mol of o2 is used ryt n thts wt i said too bt in the graph it says sulphur used the most moles o o2 as the curve for S is the highest :(
  13. sweet.sugar

    Chemistry: Post your doubts here!

    Am i invisible :/
  14. sweet.sugar

    Chemistry: Post your doubts here!

    http://papers.xtremepapers.com/CIE/Cambridge%20International%20A%20and%20AS%20Level/Chemistry%20(9701)/9701_w05_qp_1.pdf Q1-c i got D cz pb(c2h5)4 +o2 -->pbo + co2 2*4=8 c and 5*4=20h on react side so if we balance i got 8 oxy frm co2 and 10 oxygens from h2o n 1 oxy from pbo total 27 :/ Q4-c...
  15. sweet.sugar

    Chemistry: Post your doubts here!

    Thats gud :) Got some (actually 6 :D) q from m/j/06 :/ http://papers.xtremepapers.com/CIE/Cambridge%20International%20A%20and%20AS%20Level/Chemistry%20(9701)/9701_s06_qp_1.pdf Q1-D Q2-B Q10-C Q27-B Q38-B
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