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Recent content by TeKnOzOr

  1. TeKnOzOr

    Hiiii u...How are u...!!! remember me..?!? ;) :)

    Hiiii u...How are u...!!! remember me..?!? ;) :)
  2. TeKnOzOr

    Aslkm...!!! :) hOw r u dr..!? still remembEr mEe...?!? :)

    Aslkm...!!! :) hOw r u dr..!? still remembEr mEe...?!? :)
  3. TeKnOzOr

    Aslkm...!!! :) hOw r u dr..!? still remembEr mEe...?!? ;)

    Aslkm...!!! :) hOw r u dr..!? still remembEr mEe...?!? ;)
  4. TeKnOzOr

    hehe....me too can say nO...bUt chill...its ze last 2 lahh...c'mon!! :) :D Gud luck dr :)

    hehe....me too can say nO...bUt chill...its ze last 2 lahh...c'mon!! :) :D Gud luck dr :)
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  5. TeKnOzOr

    hehe...aslkm....wats up!? ready 4 tomoro?! :)

    hehe...aslkm....wats up!? ready 4 tomoro?! :)
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  6. TeKnOzOr

    :) ;) my pleasure!! :D Hmmm....A level...and u?!

    :) ;) my pleasure!! :D Hmmm....A level...and u?!
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  7. TeKnOzOr

    :) u're nice...again!! :Plol

    :) u're nice...again!! :Plol
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  8. TeKnOzOr

    HEHE...thnxx again!! yeahh...wAt a great family indeed!! :D :)

    HEHE...thnxx again!! yeahh...wAt a great family indeed!! :D :)
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  9. TeKnOzOr

    Hehee!! :D :) Jazakhallah khair!! :) AMEEN!! to you too!! thnxxx 4 this blessing post!! :) May...

    Hehee!! :D :) Jazakhallah khair!! :) AMEEN!! to you too!! thnxxx 4 this blessing post!! :) May Allah rewArd you!!
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  10. TeKnOzOr

    then you calculate its potential across it, with charge= 180C and effective capacitance= 60uf...

    then you calculate its potential across it, with charge= 180C and effective capacitance= 60uf ....obtaining 3 V ....then the total p.d across A and B = 6V + 3V = 9V <--- OK dear?!? ;) :)
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  11. TeKnOzOr

    using Q=CV , you get Q=180uC.....now, as they are in series, they have the same charge across...

    using Q=CV , you get Q=180uC.....now, as they are in series, they have the same charge across the effective capacitance which is in parallel.....
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  12. TeKnOzOr

    Hehe...ur welcome dude..!! :) :D Hmmm....yeahh....exactly man!! when they are in series, they...

    Hehe...ur welcome dude..!! :) :D Hmmm....yeahh....exactly man!! when they are in series, they have the same charge across AB because the same current flows from A to B. When they are in parallel, they have the same potential...so you first find the charge for one the first capacitor ...
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  13. TeKnOzOr

    Physics: Post your doubts here!

    (c) It is given C= 4700 uf V1= 18V V2= 12V Energy at V1= 1/2 CV1^2 = 1/2 x (4700x10^-6) x (18)^2 = 0.761 Energy at V2= 1/2 CV2^2 = 1/2 x (4700x10^-6) x ( 12)^2 = 0.338 Now, Energy during discharge = o.761- 0.338 which gives................................= 0.42 J <--- Hope u've understand...
  14. TeKnOzOr

    Physics: Post your doubts here!

    for the (ii), For a fully capacitor, Q=CV Q= 30 x 6 = 180 uC For parallel capacitor, Q=CV V=Q/C V=180/60 V= 3 V Total p.d= 6V + 3V = 9V Therefore, maximum p.d that can be sefely be applied = 9V <---
  15. TeKnOzOr

    Physics: Post your doubts here!

    so here it is: :) (b) As you know, capacitance is the reverse of resistance.....with resistor, when finding resistance of 2 resistors in series,we just add them....but in capacitor, when they are in series, we do 1/c= 1/c1 + 1/c2.....etc ....and when in parallel, we just add them...
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