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Hiiii u...How are u...!!! remember me..?!? ;) :)
Hiiii u...How are u...!!! remember me..?!? ;) :)- TeKnOzOr
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Aslkm...!!! :) hOw r u dr..!? still remembEr mEe...?!? :)
Aslkm...!!! :) hOw r u dr..!? still remembEr mEe...?!? :)- TeKnOzOr
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Aslkm...!!! :) hOw r u dr..!? still remembEr mEe...?!? ;)
Aslkm...!!! :) hOw r u dr..!? still remembEr mEe...?!? ;)- TeKnOzOr
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hehe....me too can say nO...bUt chill...its ze last 2 lahh...c'mon!! :) :D Gud luck dr :)
hehe....me too can say nO...bUt chill...its ze last 2 lahh...c'mon!! :) :D Gud luck dr :)- TeKnOzOr
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hehe...aslkm....wats up!? ready 4 tomoro?! :)
hehe...aslkm....wats up!? ready 4 tomoro?! :)- TeKnOzOr
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:) ;) my pleasure!! :D Hmmm....A level...and u?!
:) ;) my pleasure!! :D Hmmm....A level...and u?!- TeKnOzOr
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HEHE...thnxx again!! yeahh...wAt a great family indeed!! :D :)
HEHE...thnxx again!! yeahh...wAt a great family indeed!! :D :)- TeKnOzOr
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Hehee!! :D :) Jazakhallah khair!! :) AMEEN!! to you too!! thnxxx 4 this blessing post!! :) May...
Hehee!! :D :) Jazakhallah khair!! :) AMEEN!! to you too!! thnxxx 4 this blessing post!! :) May Allah rewArd you!!- TeKnOzOr
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then you calculate its potential across it, with charge= 180C and effective capacitance= 60uf...
then you calculate its potential across it, with charge= 180C and effective capacitance= 60uf ....obtaining 3 V ....then the total p.d across A and B = 6V + 3V = 9V <--- OK dear?!? ;) :)- TeKnOzOr
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using Q=CV , you get Q=180uC.....now, as they are in series, they have the same charge across...
using Q=CV , you get Q=180uC.....now, as they are in series, they have the same charge across the effective capacitance which is in parallel.....- TeKnOzOr
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Hehe...ur welcome dude..!! :) :D Hmmm....yeahh....exactly man!! when they are in series, they...
Hehe...ur welcome dude..!! :) :D Hmmm....yeahh....exactly man!! when they are in series, they have the same charge across AB because the same current flows from A to B. When they are in parallel, they have the same potential...so you first find the charge for one the first capacitor ...- TeKnOzOr
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Physics: Post your doubts here!
(c) It is given C= 4700 uf V1= 18V V2= 12V Energy at V1= 1/2 CV1^2 = 1/2 x (4700x10^-6) x (18)^2 = 0.761 Energy at V2= 1/2 CV2^2 = 1/2 x (4700x10^-6) x ( 12)^2 = 0.338 Now, Energy during discharge = o.761- 0.338 which gives................................= 0.42 J <--- Hope u've understand... -
Physics: Post your doubts here!
for the (ii), For a fully capacitor, Q=CV Q= 30 x 6 = 180 uC For parallel capacitor, Q=CV V=Q/C V=180/60 V= 3 V Total p.d= 6V + 3V = 9V Therefore, maximum p.d that can be sefely be applied = 9V <--- -
Physics: Post your doubts here!
so here it is: :) (b) As you know, capacitance is the reverse of resistance.....with resistor, when finding resistance of 2 resistors in series,we just add them....but in capacitor, when they are in series, we do 1/c= 1/c1 + 1/c2.....etc ....and when in parallel, we just add them... -
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Hehe...thnxx for the fOllow dr...!! :D :) so hw are you?! :)
Hehe...thnxx for the fOllow dr...!! :D :) so hw are you?! :)- TeKnOzOr
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Phy practical 33 on 6th Nov
hehee...dude...actually it must be in the range of 3.00-6.00.....sorry to tell you, but ur answer is wrong...me i got 3.66!! but dnt worry....there is e.c.f in this!! ;) so just chill!! :D -
Chemistry Paper 2!
Hehe....wAss a quite eAsy paperr...!! :) well,in my case i did work well...!! :) im satisfied!! :) :D Expecting between 45-55..!! :) i think the GT will not be too lOw....comparing with the past papers, this one wAs rAther better....!! CHILL!! :) -
HOW WAS CHEMISTRY PAPER 22 ?
Hehe....wAss a quite eAsy paperr...!! :) well,in my case i did work well...!! :) im satisfied!! :) :D Expecting between 45-55..!! :) i think the GT will not be too lOw....comparing with the past papers, this one wAs rAther better....!! CHILL!! :)