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  1. asd

    Physics: Post your doubts here!

    when you get a bright fringe, the waves interfere constructively i.e the phase difference is either 0* or 360* or n(360) when you get a dark fringe, the waves interfere destructively, the phase difference has to be 180* or n(180) where n is the number of order.
  2. asd

    Physics: Post your doubts here!

    Koi Meri Problem to solve karde :'(
  3. asd

    Physics: Post your doubts here!

    http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s10_qp_22.pdf 6b (i) and (ii) If for the first part we're considering that there will be a short circuit and therefore the ammeter reading is going to be 0, why doesnt the same reason go for the second...
  4. asd

    Physics: Post your doubts here!

    And yeah for the first one, daredevil has already answered. :D
  5. asd

    Physics: Post your doubts here!

    From 6bi, you know the total resistance between A and B is 960 1/960=1/1600 + 1/x 1/960=(x+1600)/1600x 1600x/960=x+1600 gives you x =2400 ohms = 2.4 kohms From the graph, we get 11 C.
  6. asd

    Physics: Post your doubts here!

    No problemo. (:
  7. asd

    Physics: Post your doubts here!

    Use the Geiger Muller tube to check the count-rate. Now place a thin sheet of paper in front of the tube, if alpha is present, it will alter the rate. Note this down. Now place an aluminium sheet in front of the tube, if it stops the radiation by the same amount, It means beta is not present...
  8. asd

    Physics: Post your doubts here!

    http://tinypic.com/view.php?pic=wslo45&s=5
  9. asd

    Physics: Post your doubts here!

    how to resolve weight? Well, just include 2 components, 1 parallel to the plane and the other perpendicular to the plane and form a triangle? See this: http://www.physicsclassroom.com/Class/vectors/u3l3e.cfm
  10. asd

    Physics: Post your doubts here!

    You do realize if you release a ball from rest on a slope it starts to move down the slope. Clearly, its the weight component "DOWN THE SLOPE" (along the slope) which makes it move down. You have to find that component which does this. In this case the car is already moving down the slope but...
  11. asd

    Chemistry: Post your doubts here!

    No problemo :D And you too, Ameen. :D
  12. asd

    Chemistry: Post your doubts here!

    Well Look here: http://www.docbrown.info/page06/OrgMechs1b.htm#catalysed
  13. asd

    Chemistry: Post your doubts here!

    If we are to react CH3CH2CH=CH2 with Hot KMnO4, we'd get a carboxylic acid and CO2, right?
  14. asd

    Chemistry: Post your doubts here!

    High bond polarity= High bond energy= reduced bond length. This means the covalent bond is strong.
  15. asd

    Chemistry: Post your doubts here!

    But we use an acid in both the reactions, and the reaction is initiated by an H(with a slightly positive charge) atom attached to the acid. Will this, then, not be an electrophilic reaction? Or is it that only addition/substitution reactions can be electrophilic or nucleophilic, and elimination...
  16. asd

    Chemistry: Post your doubts here!

    Can we describe Dehydration of alcohols and hydration of ethene as electrophilic reactions?
  17. asd

    Chemistry: Post your doubts here!

    Oh, she's a girl. :P
  18. asd

    Chemistry: Post your doubts here!

    LOL. @ the burette guy. :D
  19. asd

    Chemistry: Post your doubts here!

    Moles of NaOH that reacted with HCl will be the same as HCl's moles (ratio is 1:1) = 0.03. Moles that you'll calculate in (iii) will be the total moles of NaOH in the initial reaction that took place with (NH4)2SO4 --> 0.1. 0.03 mol of NaOH are the moles that didnt react with (NH4)2SO4 and were...
  20. asd

    Chemistry: Post your doubts here!

    For B, two products will be formed? How will CH2CCl3 be formed?
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