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  1. TimBluesWin

    Mathematics: Post your doubts here!

    No 5 (complex number), and also the differential equations thingy. Also no 9, the sin 3x thingy IIRC.... Might ask more, sorry for the inconvenience
  2. TimBluesWin

    Mathematics: Post your doubts here!

    Only me so far?? :O
  3. TimBluesWin

    Mathematics: Post your doubts here!

    Hahaha guess my way of thinking is different with yours.... :P
  4. TimBluesWin

    Mathematics: Post your doubts here!

    It's TimBluesWin btw... Are there anyone that asked for p3 solutions? :O
  5. TimBluesWin

    Mathematics: Post your doubts here!

    Isn't tan add/minus 180? Also for B I would rather square root the equation, giving sinx = sqrtroot 0.5. After finding x, don't forget that x can have two kinds values: x+360k and (180-x) + 360k.....
  6. TimBluesWin

    Physics: Post your doubts here!

    Can anybody explain to me how to do no. 7 mayjune 2009 paper 04? Thanks a lot!! :D
  7. TimBluesWin

    Give thanks to your strength and weaknesses.... :)

    Give thanks to your strength and weaknesses.... :)
  8. TimBluesWin

    Mathematics: Post your doubts here!

    I believe you can take S1 & S2 (which I do), S1 and M1, and M1 & M2..... to complement your pure math.... See here: http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_y14_sy.pdf
  9. TimBluesWin

    Thanks!!!!! :D

    Thanks!!!!! :D
  10. TimBluesWin

    From 1 till THIRTY THOUSAND!!!

    10712
  11. TimBluesWin

    Ur welcome!! Nice to meet you btw!! :D

    Ur welcome!! Nice to meet you btw!! :D
  12. TimBluesWin

    Hahaha sorry for being such a creep... :P

    Hahaha sorry for being such a creep... :P
  13. TimBluesWin

    Mathematics: Post your doubts here!

    Again, just use the quotient rule.... U=2x+3 U'=2 V=x-4 V'=1 Dy/dx=(2(x-4)-1(2x+3))/((x-4)^2) Since the denominator part of dy/dx is equal with the question, you only need to mind the numerator of the dy/dx... Hope this helps!!
  14. TimBluesWin

    Mathematics: Post your doubts here!

    Use the quotient rule. Let u=x u'=1 v=2+lnx v'=1/x dy/dx= (u'v-uv')/v^2 ((2+lnx)-1)/((2+lnx)^2) For the equation of the tangent, substitute the x=e to the equation to find the y, then substitute the e into dy/dx to find the gradient, the input your values to equation of line: y-y1=m(x-x1)...
  15. TimBluesWin

    Mathematics: Post your doubts here!

    Is it true? when I learned about the curves defined implicitly I think it's alright to include y in the dy/dx.... My math book also includes y in the dy/dx.... Also this website: http://www.phengkimving.com/calc_of_one_real_var/04_more_on_the_der/04_02_impl_diffn.htm...
  16. TimBluesWin

    Mathematics: Post your doubts here!

    I got the same answer as Haya for dy/dx.... :|
  17. TimBluesWin

    Mathematics: Post your doubts here!

    You should substitute x=7 into the original equation; this should form a quadratic equation.... then after you found both values of y, you can substitute both values into dy/dx... Hope this helps!! :D
  18. TimBluesWin

    From 1 till THIRTY THOUSAND!!!

    10710
  19. TimBluesWin

    Ur welcome!! Nice to meet you btw! :D

    Ur welcome!! Nice to meet you btw! :D
  20. TimBluesWin

    Mathematics: Post your doubts here!

    I actually got really nervous for the test in the first hour (I didn't even get whole number answer for the polynomials! When I practiced I usually got whole numbers), so I just do what I can till number 10, skipping numbers if I can't do it. At 3 o' clock I already finished no 10 (of course...
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