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  1. A

    Chemistry: Post your doubts here!

    i also took paper 31 my highest temperature recorded in the 9th minute of experiment 2 was 34. I am not sure about this because all who took the same paper in my school reached to values 46 and 50. any idea whose correct?
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    DeadlYxDemon, were you doing paper 31 chemistry or paper 21 chemistry AS

    DeadlYxDemon, were you doing paper 31 chemistry or paper 21 chemistry AS
  3. A

    lol yes, thanks for the tips on mechanics.

    lol yes, thanks for the tips on mechanics.
  4. A

    Chemistry: Post your doubts here!

    Can i explain that CCl4 is not hydrolysed by water because of the smaller atomic radius so the lone pair of the water molecules cannot be donated to the vacant d orbitals.
  5. A

    Chemistry: Post your doubts here!

    is that paper 31?
  6. A

    Chemistry: Post your doubts here!

    Anyone here appeared for the chemistry practical paper 31?
  7. A

    How did Maths 12 go? No discussion

    according to the answers i lost 14-17 marks in P1, is it still possible to get an A* or even an A in maths A level?
  8. A

    How did Maths 12 go? No discussion

    I hope that's right.
  9. A

    How did Maths 12 go? No discussion

    The problem is that i used that completing the square form in the next questions, will i loose 9 marks or will the error be carried forward?
  10. A

    How did Maths 12 go? No discussion

    farhan141 what if i forgot to factor out the 6 when i got the 2 out in q11) how many marks will i loose?
  11. A

    How did Maths 12 go? No discussion

    To find the coordinates of C i found the midpoint of AB and the gradient of AB. i used m1*m2=-1 to find the gradient of the perpendicular bisector, i used the coordinates of the midpoint AB to form an equation, then used the fact that a line is parallel to AB, so they share the same gradient but...
  12. A

    How did Maths 12 go? No discussion

    when i pluged in t=10 i got my answer as 90, thats why i gave my answer as inequality like yours, i said h>90 then solved for what t equals to. not sure though.
  13. A

    Chemistry: Post your doubts here!

    It is important to remember that with NMR, we are applying an external magnetic field to the nuclei of the atom not to the electrons.
  14. A

    Chemistry: Post your doubts here!

    In ClO3-the sum of oxidatio numbers in an ion is equal to the charge on the ion which is -1. The more electronegative element is given the negative oxidation number which is in this case oxygen.we have got 3 O atoms so their oxidation number is -2*3=-6 and Cl is +5 in order to correspond to the...
  15. A

    Chemistry: Post your doubts here!

    Kc=[Products]^n/[Reactants]^n Kc is only affected by temperature temperature in the question is the same and therefore the value of kc is the same. Suppose x moles of ethanoic acid have been used up at equilibrium. The number of moles of ethanoic acid left will be 0.5-x.For every mole of...
  16. A

    Chemistry: Post your doubts here!

    http://papers.xtremepapers.com/CIE/Cambridge%20International%20A%20and%20AS%20Level/Chemistry%20%289701%29/9701_s05_qp_4.pdf\ 4bii)
  17. A

    Chemistry: Post your doubts here!

    I am taking both AS level and A2, my major problems are with the practical papers. I am retaking chemistry AS level this year, along with the A2. Last year I scored 2 A's in my theory papers and a U grade on my practical paper. Have you got any suggestions on how I study both P3 and P5?
  18. A

    Chemistry: Post your doubts here!

    Hi, how can I prepare for my chemistry A-level exams? Iam currently revising the chapters of the book. I am worried because I haven't yet started solving past papers.
  19. A

    Paper 42 guyss !!!!!!!

    7) v=-0.2(3)^2+4(3)-15=-4.8m/s Use the following points: (0,0) (3,-4.8) a=Change in Y/Change in X=-4.8/3=-1.6m/s^2 at maximum velocity acceleration=0 m/s^2 Integrate with respect to t and set it to 0 -0.4t+4=0 t=10 seconds plug t=10 seconds into v=-0.2(10)^2+4(10)-15=5 m/s Average Velocity=Total...
  20. A

    Paper 42 guyss !!!!!!!

    6ai) From motion A to B R=mgcosα=9.6m mgsinα=ma 10*0.28=a a=2.8m/s^2 From motion B to C, the particle experiences some friction. R=mgcosα mgsinα-Ff=ma Ff=μR 10*0.28m-0.5(9.6m)=ma -2m=ma a=-2m/s^2 To find the distance AB lets add our givens a=2.8m/s^2 u=0m/s use v^2=u^2+2as v^2=2(2.8*s)...
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