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  1. M.Omar

    Maths, Addmaths and Statistics: Post your doubts here!

    wht did u get for integration question
  2. M.Omar

    Maths, Addmaths and Statistics: Post your doubts here!

    coz it,s an inverse function of the original one...get it.there is no brand new one though u cud say it was new in the sense tht it was derived frm org and diff frm original
  3. M.Omar

    Maths, Addmaths and Statistics: Post your doubts here!

    wht abt ur integration question
  4. M.Omar

    Maths, Addmaths and Statistics: Post your doubts here!

    because firstly it cud not be neg as range and domain of org function said so secondly it was to be greater than 2 i.e domain of org f and thus u cud write 2<f<infinity or simply f>2
  5. M.Omar

    Maths, Addmaths and Statistics: Post your doubts here!

    there were 2 inegrations in the whole question right?part I and 2 wht was ur integrated form
  6. M.Omar

    Maths, Addmaths and Statistics: Post your doubts here!

    wht did u get? for me it was in fraction I guess...I,ll try to remember
  7. M.Omar

    Maths, Addmaths and Statistics: Post your doubts here!

    2x = x is possible if x is zero. But zero isn't in the domain.. so.. no solution then more probably 2 marks can be achieved
  8. M.Omar

    Maths, Addmaths and Statistics: Post your doubts here!

    wht if x=0 u shud have wrote abt x>2 and all tht and also I think they wud reserve mark for the fact tht 2^x=0 is not possible because it was quite conspicuous when we made the equation
  9. M.Omar

    Maths, Addmaths and Statistics: Post your doubts here!

    so exactly proves my point since in this question f^-1>0 tht is the original domain for tht question x>2 not x>0 and hence range of f^-1>2 and so on and so tht...I think it wud be pretty clear now
  10. M.Omar

    Maths, Addmaths and Statistics: Post your doubts here!

    how does it become 2x=2? shud n,t it be 2x=x and u cud work out further
  11. M.Omar

    Maths, Addmaths and Statistics: Post your doubts here!

    last one: (cosx(1+x^1/2)x^1/2-sinx)/((1+x^1/2)^2*x^1/2) like tht
  12. M.Omar

    Maths, Addmaths and Statistics: Post your doubts here!

    it wud be (2^x-1)(2^x-1+1)=0 ab khud hi nikal lo ka kya eq 2^x-1=0 or 2^x=0 nahi banti?
  13. M.Omar

    Maths, Addmaths and Statistics: Post your doubts here!

    x>3 and f^-1>2 tht,s it
  14. M.Omar

    Maths, Addmaths and Statistics: Post your doubts here!

    since they were already sort of factorized then it wud simply be 2^x=0 not possible and 2^x-1=0 i.e x=o which was not in domain so hence no real sol
  15. M.Omar

    Maths, Addmaths and Statistics: Post your doubts here!

    Oh ho I know wht ur talking abt ...have read it in my add maths book ...but for this graph u had to check its initial domain for the orginal fx to be defined and thus for its inverse to be defined as well I know..these were the extra restrictions lg(x+1)/lg2 so x>-1 is think wht u wrote and...
  16. M.Omar

    Maths, Addmaths and Statistics: Post your doubts here!

    tht,s wht I am saying abt xtra sol which u put up tht they penalize as it violates accuracy mark..smtimes during checking they might see a general trend or sth or doubts of their own regarding xtra sol and so they hold meetings e.t.c
  17. M.Omar

    Maths, Addmaths and Statistics: Post your doubts here!

    tht,s wht I was thinking and yeah abt the equation 2^x(2^x-1)=0 wht did u write abt being no solutions...for me have already told u
  18. M.Omar

    Maths, Addmaths and Statistics: Post your doubts here!

    simply sketch its graph...mind map and whtever and see tht infact values r transposed..check the past pprs do mind map check the book even u will see tht they r transposed values..
  19. M.Omar

    Maths, Addmaths and Statistics: Post your doubts here!

    as transposed range was f^-1>2 and domain x>3 just opposite values of fx
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