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  1. hussamh10

    Mechanics M1: Post your doubt here

    1)P=Force x velocity now to find out the drivingforce when speed is 10ms 20Kw/10=2000N Now we have to find the acceleration RESULTANT force=Mass x Acc Driving force -Resistiance =Mass x Acc Acc=2000-500/12000 Acc=1.25 2)Total work done =(500 x D)+(.5(1200) x(25^2-10^2) Power=Work done/Time...
  2. hussamh10

    Mechanics M1: Post your doubt here

    Q. A particle of mass 5kg is pulled up a rough plane by a string parallel to the plane .If the plane is Inclined at 30 degrees to the horizontal ,and if the work done by the tension in the string in moving the block a distance 3m at a steady speed is 90 joules .Find the coefficient of friction...
  3. hussamh10

    Mechanics M1: Post your doubt here

    alright thanx:)
  4. hussamh10

    Mechanics M1: Post your doubt here

    isnt the coefficent be changed beacuse normal component is changed why the same coefficent is used?
  5. hussamh10

    Mechanics M1: Post your doubt here

    So plz can u explain me this question http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w10_qp_41.pdf 2nd part Q7
  6. hussamh10

    Mechanics M1: Post your doubt here

    guys i have a general question if in part 1 we are said to find the coefficient of friction of that surfacce will it remain the same even if we change the normal component and frictional force would we have to find the coefficient again if the normal component is changed??? iam really confused...
  7. hussamh10

    Mechanics M1: Post your doubt here

    Frictional force=Ta0.6-2(weight) Normal=T(0.8) (Now put the value of Ta from previous part ) You will get u
  8. hussamh10

    Mechanics M1: Post your doubt here

    Work done by frictional force=Force x distance
  9. hussamh10

    Mechanics M1: Post your doubt here

    considering forces F=ma Mgsin theta-0.875=0.8x2 8sintheta=2+0.875 SinTheta=2.875/8 =21.06 Is this the answer??
  10. hussamh10

    Mechanics M1: Post your doubt here

    thanx alot i get it :)
  11. hussamh10

    Mechanics M1: Post your doubt here

    can u do the question and explain whu TasinX=Tc sinX
  12. hussamh10

    Mechanics M1: Post your doubt here

    yeah thats the right way thanks
  13. hussamh10

    Mechanics M1: Post your doubt here

    could not have done that in paper surely God help us :)
  14. hussamh10

    Mechanics M1: Post your doubt here

    man i got every thing just cant understand why Ta Sinx=Tc sinx isnt the weight also acting downwards
  15. hussamh10

    Mechanics M1: Post your doubt here

    wouldnt be the equation like this Tc sinX=Ta sinX+The weight of da ringg??
  16. hussamh10

    Mechanics M1: Post your doubt here

  17. hussamh10

    Mechanics M1: Post your doubt here

    Ahh no problem take your time..........:)
  18. hussamh10

    Mechanics M1: Post your doubt here

    http://olevel.sourceforge.net/papers/9709/9709_s12_qp_41.pdf Q7 plzz paper after 3 days cant figure out his question leadingguy iKhaled
  19. hussamh10

    Mechanics M1: Post your doubt here

    http://olevel.sourceforge.net/papers/9709/9709_s12_qp_41.pdf Q7 plz help
  20. hussamh10

    Mechanics M1: Post your doubt here

    dont worry it was like only 2 marks
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