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  1. S

    A2 Physics | Post your doubts here

    because acceleration has to be proportional to displacement. For example the further away you full a pendulum, the faster the rate it will move down! :)
  2. S

    A2 Physics | Post your doubts here

    The problem with me was that I was looking at the ac wave which is measured by a voltmetre of fixed polarity. But the polarity of a.c changes, so with respect to the diode, the negative half cycle, that is measured by the voltmeter , is positive. I already understood all of what you were trying...
  3. S

    A2 Physics | Post your doubts here

    I understand now, but what was confusing me is that I was looking at the AC alternating voltage graph. For the first half cycle, voltage is positive, for the second half cycle, voltage is negative. I was confused how the diodes conduct during the negative half cycle, but it seems from the...
  4. S

    A2 Physics | Post your doubts here

    no intermolecular forces.
  5. S

    A2 Physics | Post your doubts here

    So In full wave rectification, the diodes convert the negative half cycle of ac into positive. I thought diodes block negative values?
  6. S

    A2 Physics | Post your doubts here

    My last thing is that, I cant seem to get the graph of the ac wave before it enters the diodes for full wave rectification. Each half cycle, current direction changes, so what is the graph of the half cycle before and after it enters the diode?
  7. S

    A2 Physics | Post your doubts here

    1000
  8. S

    A2 Physics | Post your doubts here

    ok, one more, when the current direction changes, the ac wave has the same shape? Meaning each half cycle , current direction changes? how is the graph of the current in each half cycle? and how does the diode change it? I am sorry for all the trouble I'm causing you.
  9. S

    A2 Physics | Post your doubts here

    So the ones that hassam drew on page 35 are wrong? Because that is what is confusing me!
  10. S

    A2 Physics | Post your doubts here

    uhmm but when i drew the graphs, i put half wave rectifying on the first diode. and half wave rectifying on the second diode but with a phase shift of 180 degrees. The mistake i made was not putting it on the negative side.. dont understand why? and how will the full wave rectifier form at the end.
  11. S

    A2 Physics | Post your doubts here

    not sure but I may have mis read it, or they may have penalised for writing dc instead of steady. But just to be on the safe side, we write the definition in the mark scheme, which is the steady contant voltage/current.... Can you? :D
  12. S

    A2 Physics | Post your doubts here

    can you draw the graphs for the other 2 diodes, not asked for in the question.
  13. S

    A2 Physics | Post your doubts here

    yup got it, but woe there mean value is different than r.m.s value :p dont worry i get what you mean :) but the problem sometimes, i find that they penalise for writing DC in the definition. Yup thats the best definition there is. My question is if we write DC instead of constant / steady, then...
  14. S

    A2 Physics | Post your doubts here

    ok when it mentions 240 V ac supply./ What is this 240 Volts? r.ms value?
  15. S

    A2 Physics | Post your doubts here

    1) ideal gas compressed, means work done on it i.e increases, and they come closer together Constant temperature means Internal energy is constant, so q must decrease. 2)heating of solid ---> thermal energy input / no expansion no work done. 3)melting of ice, thermal energy required to break...
  16. S

    A2 Physics | Post your doubts here

    for example j10 41 Q6 , it says dc voltage of peak value of 9 Volts, this means it has an r.m.s value?
  17. S

    A2 Physics | Post your doubts here

    does a dc voltage vary in magnitude? because it has a max value and r.m.s value?
  18. S

    A2 Physics | Post your doubts here

    -got anything about our Am bandwidth confusion? -do we include the sign of the charges while calculating electric potential?
  19. S

    A2 Physics | Post your doubts here

    Why are you complicating the problem. Work done is P x Delta V. If it asks for change in K.e then you can use 3/2 Pv = 3/2 (NkT)
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