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  1. waleedsmz

    AS Physics P1 MCQs Preparation Thread.

    Ops.. I didn't notice it had air resistance. I think Umar explained it though. It is B. :)
  2. waleedsmz

    AS Physics P1 MCQs Preparation Thread.

    Notice that the gradient of the velocity-time curve is the acceleration and not the velocity! When the first part of the graph has a very large constant gradient it means that the acceleration is constant for a long time ( The velocity is constantly increasing ). In the scenario given, the air...
  3. waleedsmz

    AS Physics P1 MCQs Preparation Thread.

    Alrighty then. I'll ask you a question first. If you have a block and push it vertically downwards on the ground, will it move horizontally ( ie change the horizontal velocity ) ? It will not. The same way if I throw a stone with an angle and an initial velocity. I can resolve the velocity that...
  4. waleedsmz

    AS Physics P1 MCQs Preparation Thread.

    A has a very large part with a constant gradient ( constant acceleration ) and this is not true since there is air resistance that gradually decreases the acceleration of the ball.
  5. waleedsmz

    AS Physics P1 MCQs Preparation Thread.

    Sure. :) When we draw a diagram of forces. We draw lines whose length are proportional to the magnitude of the forces, and if these lines make a closed triangle and the direction of each line is head to tails with the other line then the point on which the forces are acting are in equilibrium...
  6. waleedsmz

    AS Physics P1 MCQs Preparation Thread.

    13 is pretty easy. 5, 4 and 3 can make a closed triangle, meaning that it can be in equilibrium if acting on one point. Hence resultant force is zero and answer is A.
  7. waleedsmz

    Physics: Post your doubts here!

    Q.16: We know that work is the force multiplied by distance along the direction of the force. The direction of the force is obviously the field lines. So the change in work ( the change in potential energy is FS ). To make it more clear, the diagram below explains that all points on the red line...
  8. waleedsmz

    Physics: Post your doubts here!

    Q.14: This question is a tricky one indeed. First of all you need to decide at which point will you take the moment. If you look at the diagram, you'll find that you need to avoid the upper force "F" since you will not know the perpendicular distance from this force at any point on the line...
  9. waleedsmz

    Physics: Post your doubts here!

    Do you know the answer? I think it's C.
  10. waleedsmz

    Physics 42: GT ?

    It was pretty fine... Just a couple of tough questions in there...
  11. waleedsmz

    A2 Physics | Post your doubts here

    This thread will probably be dead for the next few months... It may get some life before paper 5 though... I'll surely miss it. : )
  12. waleedsmz

    Physics 42: GT ?

    Sorry bro I had variant 1. : /
  13. waleedsmz

    A2 Physics | Post your doubts here

    I'm glad your exam seems to have gone pretty well... Mine is in 5 hours... wish me luck :cry:
  14. waleedsmz

    A2 Physics | Post your doubts here

    First of all thanks for putting both the mark scheme and the question paper. ^^ i) Ok let's start by thinking about this in a way not involving any calculation. We know that if two bodies are attracting each other, then as the separation between them decreases, their potential energy decrease...
  15. waleedsmz

    A2 Physics | Post your doubts here

    I think you mean the kinetic energy one.... Not this one... I believe we don't have to derive this...
  16. waleedsmz

    A2 Physics | Post your doubts here

    Umm... Ok I'll tell you what I understand about this, although you simply don't need to know it. Conventional Current is the flow of charge from a higher potential to a lower potential. When you say a +1 ( High ) moves to a point having 0 potential for example. There is a flow of current right...
  17. waleedsmz

    A2 Physics | Post your doubts here

    I agree with what sky is saying... I think he means that the gradient of the curve is the E.M.F. and the gradient is decreasing so the value on the Y-axis on the emf is decreasing. However, we don't know the rate of decrease. In other words, we don't know the gradient of the e.m.f. ( The...
  18. waleedsmz

    I'm being followed! D: xD... Thanks bro.. Hope you like what I post xD

    I'm being followed! D: xD... Thanks bro.. Hope you like what I post xD
  19. waleedsmz

    A2 Physics | Post your doubts here

    I'm not sure about this but here is what I think: Geostationary orbiting satellites should be stationary in a certain part with respect to Earth. Meaning that if you look at a certain part in the sky you'll always find it there! A satellite in a Geostationary orbit rotates the Earth in one...
  20. waleedsmz

    A2 Physics | Post your doubts here

    Umm This is partially correct. The main idea is to check the direction of the magnetic field of a wire on the other wire.Which is in this case coming out of the paper... Sometimes it may get into the paper. I don't know what the examiner could put in there so I just wanted to give you a heads up. ;)
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