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Search results

  1. shafayat

    Hardest Chemistry MCQs ever.

    C.. I thinkso its C
  2. shafayat

    AS Practical list

    NO
  3. shafayat

    Thanks yaar ! N same to u :D

    Thanks yaar ! N same to u :D
  4. shafayat

    miss maria did sent me ! thats y I asked if u wanted ... anyways thx ! :P

    miss maria did sent me ! thats y I asked if u wanted ... anyways thx ! :P
  5. shafayat

    oee ! Salam ! u have the p1 bio revision thingy ?

    oee ! Salam ! u have the p1 bio revision thingy ?
  6. shafayat

    Physics, Chemistry and Biology: Post your doubts here!

    I acctually wanted an official defination .. =] plz
  7. shafayat

    Physics, Chemistry and Biology: Post your doubts here!

    plz can sm1 give the defination of the mole and avogardos constant ?
  8. shafayat

    same to you bro... InshaAllah

    same to you bro... InshaAllah
  9. shafayat

    umn.. I got phy on 29 n chem on 30 ... nuthing else ... nuthin much

    umn.. I got phy on 29 n chem on 30 ... nuthing else ... nuthin much
  10. shafayat

    SUP?

    SUP?
  11. shafayat

    physics paper 3, harder than hard

    dude its POWER dessicipated .. how r u measuring it in volts ?
  12. shafayat

    physics paper 3, harder than hard

    I wrote 8 but my teaachers say its 32 :[
  13. shafayat

    physics paper 3, harder than hard

    dun remember but (I^2 R)
  14. shafayat

    physics paper 3, harder than hard

    b btw the fuse n bulb question . the answer is 32
  15. shafayat

    physics paper 3, harder than hard

    not this time bro ! maybe 58-64
  16. shafayat

    physics paper 3, harder than hard

    majority IN MY SCHOOL got 33.1%
  17. shafayat

    physics paper 3, harder than hard

    the Tshirt was an easy one ! all abt evaporation
  18. shafayat

    physics paper 3, harder than hard

    the total energy input was .. the loss + the useful power they said mgh= loss /sec .. then u add the useful power ! then u get the total power output
  19. shafayat

    physics paper 3, harder than hard

    becuz u wrote in the denominator ...only the power LOSS .. u didnt add the USEFUL POWEROUTPUT to get the TOTAL POWER INPUT .... u just put the value from the mgh in this n left it like that !! but in the question its clearly stated ! TAKE THIS AS THE POWER LOSS / second !!! so u will have to...
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