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Mathematics: Post your doubts here!
The final value should not include the variable x. I think it should be a typo in the problem you listed. -
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Chemistry: Post your doubts here!
The work and answer are shown in the image. A simpler way to think is that no matter how much R is generated, the amount of P + Q always stays at 2. Therefore, the amount of P consumed must equal the amount of Q generated. This means P and Q have the same stoichiometric coefficient. Again... -
Mathematics: Post your doubts here!
If you calculated correctly in part (ii), the loci should be: y = x - 1 x^2 + (y - 1)^2 = 4 Where x is the real part and y is the imaginary part. Now, to find the intersection points of the loci is the same as to find sets of x and y that satisfy both of the equations. To do that, simply plug... -
Further Mathematics: Post your doubts here!
I don't think so. A-level Mathematics consists of Pure Mathematics 1, 2 & 3, Mechanics 1 and Statistics 1; Futher Mathematics includes Further Pure Mathematics (which is different from the Pure Mathematics book and, obviously, much thinker and heavier :cry: ), Mechanics 2, 3 & 4, and "A Concise... -
Current : Is it a vector or a scalar quantity?
You can regard current as a quantity with only one direction. Then it is a scalar. ;) -
Current : Is it a vector or a scalar quantity?
Yeah it's like the addition and subtraction of odd and even numbers :P This is quite useful. -
HOW WAS PHYSICS PAPER 5 PPL ? HOW WAS YOUR EXAM ?
I mean the linear speed of the wind vane. I put it between the fan and the balloon. So the wind from the fan can make it rotate, and its linear speed is very close to that of the wind. -
HOW WAS PHYSICS PAPER 5 PPL ? HOW WAS YOUR EXAM ?
I used the wind vane. It's not a very high-tech apparatus but it is useful. The wind vane has a rotating part that revolves when wind blows. So I think if the wind vane is light enough, its rotating linear speed should be the same as wind speed. Here what needs to be recorded is something like... -
Further Mathematics: Post your doubts here!
I don't remember them all, but these should be of use: projection length a onto b = a dot b / |b| distance between two skew lines l1 and l2: find a point A on l1 and B on l2 distance = AB dot (l1 cross l2) / |l1 cross l2| distance between two parallel planes: similar to the lines distance... -
Further Mathematics: Post your doubts here!
Ouch I know where I got wrong... In D, the numbers are 1, 5 and 7. Here 7 is the largest. So we need to ensure that -1 < 7 k < 1. The answer is then that stated on the MS. Sorry about my mistake. :P -
Further Mathematics: Post your doubts here!
I think you ask for answer to the EITHER part, right? First part Second part -
Further Mathematics: Post your doubts here!
This is how I think (I'm not sure if it is nonsense :P) k^n × A^n = (k^n) P (D^n) (P^-1) = P × (k A)^n × P^-1 So I think just need to ensure that k A has all elements less than 1 and greater than -1. Then the whole thing tends to 0 as n gets larger. Here the Diagonal matrix you came up with... -
Further Mathematics: Post your doubts here!
First part: Use the equilibrium of moments. Second part: -
Tomorrow for the Chemistry P4... Hope that I'm not preparing to fail it. :P
Tomorrow for the Chemistry P4... Hope that I'm not preparing to fail it. :P- DragonCub
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Chemistry P4| A2 only
(c) Use only one kind of monomer and "poly" it to get a homopolymer. I recommend that you use CO2HCHRNH2. It's simpler to draw. BE AWARE: you cannot choose ethan-1,2-diol, OHCH2CH2OH, since it does not possess the functional group CO2H to initiate esterification. The "poly" version of this... -
Chemistry P4| A2 only
(b)(iii) Thickness can be one. The thickness represents how hard it is for the drug to go through the hydrogel. Also the more thick the more time it takes Using different chemicals or materials to make the hydrogel can affect the rate of reaction with HCl and so the rate of release. Making... -
Chemistry P4| A2 only
The general idea is like this: X(n) = X(n-m) + m e(-) [numbers in the round brackets represent charge] There is an equilibrium position in the middle. According to Le Chatelier's Principle, increasing the conc. of one side would favour the reaction and shift the euqi. position towards the other...