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  1. umarashraf

    Chemistry: Post your doubts here!

    yes.. the answer is C but due to lack of skills i cant draw all the structures here..but can guide you just by sayin k if you use 1 cl, you can only have 1 orientation .. by using 2,3orb 4 carbons you can only make 2 2 and 2 orientations of the structure of chloroethane...
  2. umarashraf

    A2 Physics | Post your doubts here

    yes... u r right mate...
  3. umarashraf

    Chemistry: Post your doubts here!

    mate first of all .. alcohols donot react with sodium hydroxide... secondly propanoic acid is an acid while sodium hydroxide is a base... this will readily react and form salt + h2O.... (acid base titration)
  4. umarashraf

    Chemistry: Post your doubts here!

    do you know have any concept about diagonal relationship of periodic table...???
  5. umarashraf

    Chemistry: Post your doubts here!

    again u welcome...
  6. umarashraf

    Chemistry: Post your doubts here!

    oh goog... look.. we have 3 products.. ethene methane and propene... if i mole is produced by cracking, then o.5% will be of ethene(as mentioned in the q) then 0.25 of propene and .25 of methane is produced... .25+.25+.5=1... to convert .25 into proper fraction, we need to multiply it by 4...
  7. umarashraf

    Chemistry: Post your doubts here!

    is the answer B...?? if yes then i think i can explain u easily..if not then... ... ... :)
  8. umarashraf

    Chemistry: Post your doubts here!

    alkenes are nothing.. but arenes have a ring of pie electrons which behaves as strong strong nuclophile....
  9. umarashraf

    Chemistry: Post your doubts here!

    u welcome..
  10. umarashraf

    Chemistry: Post your doubts here!

    compressing at constant temp will never liquify any gas... you have to cool the cylinder as well for liquifying... else the cylinder will blast away....
  11. umarashraf

    A2 Physics | Post your doubts here

    the intensity of the electrons is to be kept constant.... look , if electrons come with high energy, they should come in lower amount to keep the intensity constant.... and if they come with lower energy, they should come in high numbers to keep the intensity constant.... hope you can understand....
  12. umarashraf

    Mathematics: Post your doubts here!

    expand (1+ax)65 and multiply by (1-2x)... add the coefficients of x and put that equal to Zero.... i think the answer is 2/5... right...???
  13. umarashraf

    Mathematics: Post your doubts here!

    10K^3 /9=30.... .. i have solved its twice now... its again equal to three...
  14. umarashraf

    Mathematics: Post your doubts here!

    for the first part... take the first derivative... then put that equal to zero... put the value of x you have got into the real equation to get the value of y... i think it fx<2... for second. b^2-4Ac=0
  15. umarashraf

    Mathematics: Post your doubts here!

    i dont have marking scheme.. but what is the answer..??? by k^3 its comes 3...
  16. umarashraf

    Mathematics: Post your doubts here!

    mate open the formula sheet and follow the first formula used there for expansion... 5C2[k]^3[1/3]^2=30 and solve this... k=3.. i thinks its the answer...????
  17. umarashraf

    oh than its fine:)

    oh than its fine:)
  18. umarashraf

    i mean many people likes your previous avatar and u have changed the real identity

    i mean many people likes your previous avatar and u have changed the real identity
  19. umarashraf

    i guess you were praised rather too much for that Avatar...???:)

    i guess you were praised rather too much for that Avatar...???:)
  20. umarashraf

    ohh... good...:)

    ohh... good...:)
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