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  1. Aarjit

    Mathematics: Post your doubts here!

    [Q3] The random variable X is the length of time in minutes that Jannon takes to mend a bicycle puncture. X has a normal distribution with mean μ and variance σ^2. It is given that P(X > 30.0) = 0.1480 and P(X > 20.9) = 0.6228. Find μ and σ. X ~ N (μ , σ^2) P(X > 30.0) = 0.1480 or, P [z >...
  2. Aarjit

    Mathematics: Post your doubts here!

    you're looking for a number 'n', where 5000 < n < 6000 [or more precisely, the smallest and the largest number you can possibly achieve is 5123 and 5643 respectively] .. can't ever start with 6, can it? ;)
  3. Aarjit

    Mathematics: Post your doubts here!

    Alright, I got it. It really is worth a thought.. After giving a minute or so for the hit and trial strategy, I inferred the following criteria for a 7-digit number to be divisible by 4: #1. The last digit MUST be even (4 or 2 or...
  4. Aarjit

    Mathematics: Post your doubts here!

    Here, check this out: Each of the digits 1,1,2,3,3,4,6 is written on a separate card. The seven cards are then laid out in a row to form a 7-digit number. How many of these 7-digit numbers are divisible by 4? [Ans:300]
  5. Aarjit

    HOW was biology PAPER 42?

    Application overload: hardly any core! extensive like plain-vanilla. GT (A) ~ 66 - 72. P.S. no paper discussion ppl: T - 1900. :)
  6. Aarjit

    A2 Biology | Post your doubts here

    Application overload: hardly any core! extensive like plain-vanilla. GT (A) ~ 66 - 72. P.S. no paper discussion ppl: T - 1900. :)
  7. Aarjit

    Mathematics: Post your doubts here!

    :eek: Seriously? try "I LATE" (think that you're always late at learning maths! ;)) in ∫ u.v'(x)dx = u.v − ∫ u'(x).v dx,"u" will take the expression in the following oder: a I - Integration (~ by parts) L - Logarithmic (e.g. lnx, logx) A - Algebraic (e.g. x^2, 2x) T - Trigonometric (tanx...
  8. Aarjit

    Mathematics: Post your doubts here!

    So that we can cancel out sec² Ө even before we begin integrating! 1 + tan² Ө = sec² Ө ; ∫1/(1 + x²) dx ; dx = sec² Ө . dӨ............... [do you see it now? ;)] ∫1/(1 + x²) dx suppose x = tan Ө so Ө = tan^(-1) x so 1 + x² = 1 + tan² Ө = sec² Ө and dx/dӨ = sec² Ө dx = sec² Ө . dӨ...
  9. Aarjit

    Mathematics: Post your doubts here!

    This is how you do it: ∫1/(1 + x²) dx suppose x = tan Ө so Ө = tan^(-1) x so 1 + x² = 1 + tan² Ө = sec² Ө and dx/dӨ = sec² Ө dx = sec² Ө . dӨ So ∫1/(1 + x²) dx = ∫(1/sec² Ө) . sec² Ө dӨ = ∫ 1 dӨ = Ө + k = tan^(-1) x + k credit...
  10. Aarjit

    Mathematics: Post your doubts here!

    sqr(10).cos [2 θ - 71.6'] = 2 ; 0' < θ < 90' >> 2 θ - 71.6' = cos–1 [2 /sqr(10)]..... ......................= 50.8' >> θ = (50.8' + 71.6'] / 2 = 61.2' also, 2 θ - 71.6' ~ 360' - 50.8' [since, cosθ = cos(360-θ) = cos(-θ)] >> 2θ = 380.8' ~ 20.8' [since, 380.8' = 360' (1 complete rotation) +...
  11. Aarjit

    Mathematics: Post your doubts here!

    y = (e^2x)/[1+(e^2x)] dy = 2e^(2x)[1+e^(2x)] - e^(2x).2e^(2x) dx.....clever,eh?[1+e^(2x)]^2 .....= 2e^(2x) + 2e^(4x) - 2e^(4x) ......................[1+e^(2x)]^2 .....= ___2e^(2x) ___ .............[1+e^(2x)]^2 x= ln3; .....= ___2e^(2.ln3) ___ .............[1+e^(2.ln3)]^2 .....= ___2e^(ln9)...
  12. Aarjit

    Mathematics: Post your doubts here!

    ...because OP is perpendicular to AB and so is plane OAB! OP falls in the region of OAB. Saying that OP is in the plane OAB is exactly like saying ~ AB is in the plane which you need to solve for. P.S. A rough sketch will make the situation easier to perceive.
  13. Aarjit

    Mathematics: Post your doubts here!

    You have: OP = (2/3 5/3 7/3) [from (ii)] Since AB and OP are orthogonal, and the plane you're solving for contains AB, OP must be orthogonal to the plane as well! Take out the scalar factor (1/3) to find the normal vector n ; >> n = (2 5 7) you have A (1 2 2); now, the requisite equation for...
  14. Aarjit

    applies for every paper, till the very end.. :P

    applies for every paper, till the very end.. :P
  15. Aarjit

    Happy belated Birthday, bro! :)

    Happy belated Birthday, bro! :)
  16. Aarjit

    hey. Practice Q1. 33/O/N/09 and 35/O/N/11.

    hey. Practice Q1. 33/O/N/09 and 35/O/N/11.
  17. Aarjit

    PHYSICS 9702 P3 help!!!

    Exactly! You need to compare your uncertainty in the two (or more) values of k with EITHER the individual % uncertainty of k OR simply compare it with the standard acceptable uncertainty of 20%; albeit, you will have to mention the latter in your answer. The examiner can't just 'consider' that...
  18. Aarjit

    PHYSICS 9702 P3 help!!!

    There can be two possible limits for the accuracy of imperial values. Let us suppose an arbitrary variable 'k'; [1] lim (% uncertainty in k) = k1+k2+k3+...+kn * 100% [for comparison with k's individual uncertainty] pretty clever, eh?.............................k(mean) [2] 20% standard...
  19. Aarjit

    How was Math P1??????

    the second term if a GP is 9 less than the first term. The sum of the second and third terms is 30. Given that all terms are positive*, find the value of the first term. a.r = a - 9 ; a.r + a.r^2 = 30 >> r = (a - 9)/a >> 30 = (a - 9) + a.[(a-9)/a]^2 >> 30 = a - 9 + (a-9)^2/a >> 39.a = (a^2) +...
  20. Aarjit

    How was Math P1??????

    Let me see how far I can recall.. ;) tanx + 1/tanx = (sinx/cosx)+(cosx/sinx) = (sin^2 x + cos^2 x)/sinx.cosx = 1/sinx.cosx Q.E.D now, solve for 2/sinx.cosx = (an expression with tanx); 0 < x < 180 >> 2*(tanx + 1/tanx) = (RHS) [from the first part] factorize to get (tanx - 1)(tanx + 2) = 0 >>...
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