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  1. biscuitbiscuit

    Mathematics: Post your doubts here!

    Its easy in the book but when it comes to past papers I am blank
  2. biscuitbiscuit

    Mathematics: Post your doubts here!

    Thanks
  3. biscuitbiscuit

    Mathematics: Post your doubts here!

    Its okay if u got tired of answering
  4. biscuitbiscuit

    Mathematics: Post your doubts here!

    Thanks. For 'Q6' how to do the second sub-part, http://papers.xtremepapers.com/CIE/Cambridge%20International%20A%20and%20AS%20Level/Mathematics%20(9709)/9709_s07_qp_1.pdf
  5. biscuitbiscuit

    Mathematics: Post your doubts here!

    Okay. For 'Q7' I'll find the mid-point of AB than the gradient of AB and use it to find the equation of the perpendicular bisector. Can you tell how will i find the co-ordinate of D"...
  6. biscuitbiscuit

    Mathematics: Post your doubts here!

    Thank you so much. For this question tell me if I am doing correct, first I'll find the gradient of AB and use it to find the gradient of DA and its equation. Than the equation of DC and for the co-ordinates i'll solve them...
  7. biscuitbiscuit

    Mathematics: Post your doubts here!

    Well tell me the procedure and if i am not able to solve than the whole thing
  8. biscuitbiscuit

    Mathematics: Post your doubts here!

    Someone solve 'Q5" http://papers.xtremepapers.com/CIE/Cambridge%20International%20A%20and%20AS%20Level/Mathematics%20(9709)/9709_s05_qp_1.pdf
  9. biscuitbiscuit

    Mathematics: Post your doubts here!

    Thanks
  10. biscuitbiscuit

    Mathematics: Post your doubts here!

    I think you took the wrong factors for the equation 'h^2 - 12h + 64 = 0' because when you multiply -16*4 you get -64 instead of getting +64
  11. biscuitbiscuit

    Mathematics: Post your doubts here!

    Someone please solve 'Q9' and do explain why (i) is 6 and skip (ii) if you want http://papers.xtremepapers.com/CIE/Cambridge%20International%20A%20and%20AS%20Level/Mathematics%20(9709)/9709_w09_qp_12.pdf
  12. biscuitbiscuit

    Mathematics: Post your doubts here!

    Thanks
  13. biscuitbiscuit

    Mathematics: Post your doubts here!

    Thank you so much. Now can you tell me how will I find the co-ordinates of the other two vertices and btw the first equation should be '2x - y = 3'
  14. biscuitbiscuit

    Mathematics: Post your doubts here!

    "Two sides of a parallelogram are formed by parts of the line 2x -y = -9 and x - 2y = -9." I was able to find the find co-ordinates of the vertex where they intersect which is (-3,3). The next part says that another vertex of the parallelogram is the point (2,1) and I have to find the equations...
  15. biscuitbiscuit

    Mathematics: Post your doubts here!

    "Two sides of a parallelogram are formed by parts of the line 2x -y = -9 and x - 2y = -9." I was able to find the find co-ordinates of the vertex where they intersect which is (-3,3). The next part says that another vertex of the parallelogram is the point (2,1) and I have to find the equations...
  16. biscuitbiscuit

    thanks ;)

    thanks ;)
  17. biscuitbiscuit

    Mathematics: Post your doubts here!

    Thanks :)
  18. biscuitbiscuit

    Mathematics: Post your doubts here!

    Guys can you solve this " In a triangle OAB, O is the origin, A is (0,6) and B is (6,0). Find the equations of the three medians of the triangle"
  19. biscuitbiscuit

    Further Mathematics: Post your doubts here!

    Hi guys, can someone do this one please ' In a traingle OAB, O is the origin, A is the point (0,6), B is (6,0). Find the equation of the three medians of the triangle.'
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