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  1. The Sarcastic Retard

    Mathematics: Post your doubts here!

    The domain is responsible for it. if domain is x < vertex then -ve sign and viceversa
  2. The Sarcastic Retard

    Chemistry: Post your doubts here!

    awesomaholic101
  3. The Sarcastic Retard

    Mathematics: Post your doubts here!

    L Like* according tto me there is no trick to it, u just need ur logic.
  4. The Sarcastic Retard

    Mathematics: Post your doubts here!

    2(i) 4x^2 - 12x 4(x^2 - 3x) 4((x-3/2)^2 - 9/4) 4(x - 3/2)^2 - 9 = 1 * ( 2 * (x - 3/2))^2) - 9 -------------------> (2x - 3)^2 - 9 (ii) 4x^2 - 12x - 7 > 0 2x(2x - 7)+1(2x - 7) > 0 (2x+1)(2x-7)>0 x<-1/2 and x>7/2
  5. The Sarcastic Retard

    Chemistry: Post your doubts here!

    Optical isomer.
  6. The Sarcastic Retard

    Chemistry: Post your doubts here!

    All you need is a good grasp on the concept. That's it. :) Still 2 days are there, practice as many things u can.... But remember u should know ur every concepts. :)
  7. The Sarcastic Retard

    Chemistry: Post your doubts here!

    (iii) We are asked to find number of moles of compound in 250cm^3 we found its mole in 25cm^3 in part (ii) --> (250 * 5 * 10^-3)/25 = 0.05 mol (iv) Mr = m/n = 6.3/0.05 = 126 (v) Mr of H2C2O4 = 90 So 126 - 90 = xH20 That is 36 Mr of H2O = 18 so x is 2
  8. The Sarcastic Retard

    Mathematics: Post your doubts here!

    -45+29 = -16 E(x - 45) = -148 - 16 = -164 E(x - 45)^2 = 3089 + 16^2 = 3345 Now u can solve it
  9. The Sarcastic Retard

    SAhi hai

    SAhi hai
  10. The Sarcastic Retard

    Thanks on 12th Chem.

    Thanks on 12th Chem.
  11. The Sarcastic Retard

    Chemistry: Post your doubts here!

    1) Mole fraction = [No. of mole of molecule]/[No. of total moles] Let mole fraction = X X(C2H4) = 0.5 So we can assume no. of moles of CH4 and C3H6 to be 1 and C2H4 to be 2 so that 2/(1+2+1) = 0.5 mol So we have products as CH4 + 2C2H4 + C3H6 Total of 8 C and 18 H Therefore answer is C8H18...
  12. The Sarcastic Retard

    I am great..... Howz eu? ;)

    I am great..... Howz eu? ;)
  13. The Sarcastic Retard

    Hhie

    Hhie
  14. The Sarcastic Retard

    Chemistry: Post your doubts here!

    Esterification in A and B and elimination in C
  15. The Sarcastic Retard

    Mathematics: Post your doubts here!

    Eqn of Line : y = -3/4x + 12 Area = x * y = 12x - 3/4*x^2
  16. The Sarcastic Retard

    Chemistry: Post your doubts here!

    Kc = [CO][H2O]/[CO2][H2] 1.44 = (0.2+x)^2 / (0.5-x)^2 sqrt(1.44) * (0.5-x) = 0.2+x 0.6 - 1.2x = 0.2 + x 0.4 = 2.2x x = 0.18 Equilibrium moles of CO and H2O= 0.2 + 0.18 = 0.38 and of CO2 and H2 = 0.32
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