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  1. Saad Mughal

    Biology; Chemistry; Physics: Post your doubts here!

    The current is always the SAME throughout in a series circuit. Which means, that even if you increase the resistance or decrease it, the current through each resistor will be the same. This means that the voltage across each resistor = IR. So, since the current is same, the one with the higher...
  2. Saad Mughal

    Addmaths paper 1

    Did you do b^2 - 4ac = 0?
  3. Saad Mughal

    Computer studies atc!

    Was it a dark pencil?
  4. Saad Mughal

    General paper discussion

    Yes.
  5. Saad Mughal

    "bki paper went brilliant ALHUMDULILLAH." ^Read up, me boy. 60 main say 15 marks nikaal doge tou...

    "bki paper went brilliant ALHUMDULILLAH." ^Read up, me boy. 60 main say 15 marks nikaal doge tou horrible hojata hai.
  6. Saad Mughal

    Maths, Addmaths and Statistics: Post your doubts here!

    5^y/125^x-2 = 25 5^y/5^3x-6 = 5^2 Simplifying, y - 3x + 6 = 2 y - 3x = -4 This is equation (ii). Simultaneously solve it with the one in part (i) to get x and y.
  7. Saad Mughal

    Addmaths paper 1

    Not really. Trigonometry, Modulus Graphs and Linear Law are all just graph sketching and plotting. They're kinda like the 'free marks' of the paper. If vectors for the unknowns 'lambda' and something come, it'll be easy peasy. Circular Measure and Applications of Integration are easy too. SOME...
  8. Saad Mughal

    Computer Studies Notes + Tips + Queries

    In the Nov. 2012 paper, it wasn't, or I didn't see it.
  9. Saad Mughal

    Addmaths paper 1

    It will be of Relative Velocity, Vectors, Circular Measure (Q.12), Applications of Integration, Modulus Graphs, Linear Law, Trigonometry.
  10. Saad Mughal

    Addmaths paper 1

    360 60 36
  11. Saad Mughal

    Addmaths paper 1

    The DISTANCE was 0.
  12. Saad Mughal

    Addmaths paper 1

    Yeah, again at O. It was at O at t=0. Then, s = 18t^2 - t^3. When s = 0 (i.e. it is AGAIN at O). t^3 = 18t^2 t = 18 s v = -324 m/s.
  13. Saad Mughal

    Computer Studies Notes + Tips + Queries

    No. The one I solved, the Nov. 2012 one, we used 1024. If we used 1000 we get a error of more than 0.5. I was confused too. I'm used to it, their OWN endorsed books go against their mark schemes.
  14. Saad Mughal

    Addmaths paper 1

    4<k<12
  15. Saad Mughal

    Addmaths paper 1

    25/4 = nC2 (1/4) - nC1(1/2) 25/4 = n(n-1)(n-2)!/2!(n-2)! (1/4) - n(n-1)!/1!(n-1)! (1/2) 25/4 = n^2 - n/8 - n/2 50 = n^2 - n - 4n n^2 - 5n - 50 = 0 Simplifying gives n=10 and n=-5 (rej.). Please give the question for the trigonometry one, I'll solve.
  16. Saad Mughal

    Addmaths paper 1

    6 s.
  17. Saad Mughal

    Computer Studies Notes + Tips + Queries

    You've read the IGCSE book, right? It's written correctly there that 1 Megabyte = 1000 Kilobytes. However, 1 Mebibyte = 1024 Kibibytes. Mega and Kilo are part of the standard SI unit tables. 1 Kilo = 1000 of a unit. 1 Mega = 10^6 of a unit.
  18. Saad Mughal

    Addmaths paper 1

    864 m. 324 m/s.
  19. Saad Mughal

    Addmaths paper 1

    Then how did you get it wrong? o_O
  20. Saad Mughal

    Computer Studies Notes + Tips + Queries

    I haven't done a lot of past papers. The ones that I have done contained 1 of these. Their easy, although I don't get why 1 Megabyte = 1024 Kilobytes. That's wrong.
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