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  1. Saad Mughal

    Biology; Chemistry; Physics: Post your doubts here!

    The problem is that bistable circuits have NOR gates that are cross coupled, their truth tables are more complex than the others! Here is the image the I have in my book.
  2. Saad Mughal

    Biology; Chemistry; Physics: Post your doubts here!

    I read it off the internet and from the Stephen Pople book. I'll explain it to you in another way. Bistable circuit consists of two NOR gates (simple bistable circuit, the circuit diagram is irrelevant) that are cross-coupled. It may work in a fancy manner but its task is ultimately to keep one...
  3. Saad Mughal

    [Game] | MALE Vs. FEMALE

    5470
  4. Saad Mughal

    Biology; Chemistry; Physics: Post your doubts here!

    I haven't either. :D However, its in the syllabus, use of bistable circuits and how they exhibit memory. use of astable circuits and how resistance/capacitance affects the frequency.
  5. Saad Mughal

    [Game] | MALE Vs. FEMALE

    ^^That's unfair. :p 5430
  6. Saad Mughal

    [Game] | MALE Vs. FEMALE

    5420 again. :(
  7. Saad Mughal

    [Game] | MALE Vs. FEMALE

    5420
  8. Saad Mughal

    [Game] | MALE Vs. FEMALE

    5410
  9. Saad Mughal

    [Game] | MALE Vs. FEMALE

    5400 Do we have enough time to do this? :p
  10. Saad Mughal

    Biology; Chemistry; Physics: Post your doubts here!

    Bistable circuits are circuits that consist of logic gates (NOR gates from what I've learnt) that has ONE stable output for the two inputs. If you change one of the inputs (only one pulse is needed to change it), then the output flips to the other STABLE output (e.g. if it was 0 it would become...
  11. Saad Mughal

    Biology; Chemistry; Physics: Post your doubts here!

    NH4NO3 (heated) ----> 2H2O (g) + N2O (g) They've told us that the ammonium nitrate decomposes to steam and gas X so just write down the equation, NH4NO3 (heated) ----> 2H2O (g) + ____ Deduce the gas by comparing on both sides. Hope that helps :)
  12. Saad Mughal

    Biology; Chemistry; Physics: Post your doubts here!

    This belongs in the Mathematics section :p Still, Median for even number = n/2 th term, n+2/2 th term, Therefore, Median = 12/2 , 14/2 = 6th and 7th term, From table, Median = 2+3/2 Median = 2.5 Hope that helps. :)
  13. Saad Mughal

    Biology; Chemistry; Physics: Post your doubts here!

    Yes. :( Well, thanks for trying. :)
  14. Saad Mughal

    Biology; Chemistry; Physics: Post your doubts here!

    I made the same calculations and assumed it to be 0.6 m. However, the answer is 0.5 m.
  15. Saad Mughal

    Biology; Chemistry; Physics: Post your doubts here!

    In part (e), we deduced the fact that 25.7 cm^3 of volume is used to titrate a 25 cm^3 sample of T, right? Through the 25.7 cm^3, we calculated the no. of moles. of potassium manganate (VII) in (f) by using the No. of moles = Concentration * Volume formula; the number of moles of POTASSIUM...
  16. Saad Mughal

    Biology; Chemistry; Physics: Post your doubts here!

    Can anyone help me with part (f) and (g)? P.S. The picture quality is poor, uploaded in a hurry. If you can't read them then just see the diagram, The parts are, (f) The man now walks past A towards the left-hand of the plank. What is the upward force from the trestle at B at the instant the...
  17. Saad Mughal

    Calculators

    Yes it is allowed.
  18. Saad Mughal

    Biology; Chemistry; Physics: Post your doubts here!

    Your method is correct. And that should be the correct answer as well. Just like TheStallion-Reborn stated, since both the concentrations are in dm^3, you simply have to calculate the mass(g) of 1.43 moles of HCL using the formula (Mass = No. of moles * Mr/Ar) so this would simply get the...
  19. Saad Mughal

    Maths, Addmaths and Statistics: Post your doubts here!

    All these are correct except for two tiny mistakes. In 4- it will be 1-0.0001 = 0.999 since we're taking out the probability of fail in first four months. In b, 1- it will be (0.1)^n.
  20. Saad Mughal

    Hehe Thanks! :D

    Hehe Thanks! :D
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