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Chemistry: Post your doubts here!
to find values of a,b and c 1st) if eqn 1 is slowest rexn then rate only depends upon the concentration of [H2O2] and [I-] that is value of c is automaticall 0. and since the molar ratio in the given equation is 1:1 your values will be a=b=1. 2nd) If equation 2 is the slowest rexn. then u have... -
Physics: Post your doubts here!
In Q1, u=0 for vertical component not for horizontal, so there is use of u = 0 in MS -
Mathematics: Post your doubts here!
2)i) Use this formula ( 1- 3/2x)^6 = 6C0*1 + 6C1 * 1 * (-3/2x) + 6C2 * 1 * (-3/2x)^2 + 6C3 * 1 * (-3/2x)^3 +................ evaluate it u will get the terms including x^2 and x^3 ii) here, use above expanded equation to find terms with x^3 i.e. (k + 2x)( 6C0*1 + 6C1 * 1 * (-3/2x) + 6C2 * 1 *... -
Chemistry: Post your doubts here!
Q3--> Use box electronic configuration Q31--> Dipole moment 0 in each part of kelvar molecule Q38----> Hydrogen bonding is not suitable except in CBrF3 -
Chemistry: Post your doubts here!
1---> D because use the formula to calculate the mole ratio to do this follow these steps i) change % composition to no. of moles i.e. % composition / molar mass ii) divide number of moles by lowest no. of moles iii) if mole ratio is in fraction then multiply it by suitable no. to make it whole... -
Chemistry: Post your doubts here!
given, mass of NaN3= 50g i.e number of moles = 50 / 130 = 0.385 moles now from the given equation, 2 moles of NaN3 gives 3 moles of N2 0.385 moles of NaN3 gives 3/2 * 0.385 = 0.577 moles of N2 At RTP, Molar volume of any gas - 24 dm3 n = produced volume / Molar volume --> 0.577 = v/ 24 i.e. v... -
Chemistry: Post your doubts here!
See the number of bond pairs and lone pairs in the central atom... Expected bond angles according to the number of electron pairs available: 1) 2 ------> 180 (linear shape) 2) 3-------> 120 (trigonal planar) 3) 4-------->109 (tetrahedral) Above are most commonly asked bond angles But presence... -
Chemistry: Post your doubts here!
trigonal planor means obviously 3 pairs in central atom, here there are 2 bond pairs (1 single bond and next double bond) another one is lone pair.....the expected angle is 120 and there will certainly be effect of lone pair but it won't affect too much that its angle decreases to 109 there... -
Physics: Post your doubts here!
U have formula for phase angle, P(let phase angle) = t/ T(time period) * 360 as a complete cycle denotes 360 degree use this to calculate value of t.... phase angle = 60 as T2 lags behind by 60 degree T= 3 secs (Time period of given wave) now, 60 = t/3 * 360 i.e. t = 0.5 secs as amplitudes... -
Chemistry: Post your doubts here!
for 2 its B) Carbon as it has total of 2 electron pairs and and 2 unpaired electrons in 2 principle quantum orbital (Draw box electronic configuration to see that) for 5) its C because double bond acts as a single bond pair... -
Significant Figures
Better use your original values (apart from round off value), coz this will lead your answer to accuracy. if you use round off value, there is less chance of getting accuracy mark for your answer. However in some cases such answers are too given marks. Your round off values are just to satisfy... -
A-Level Mathematics
Anyone getting problem in any of the math problems, post your questions here so that they could be solved................ thanks -
CIE S1 Book help on Probability and Expectation & Variance Questions
Question number 11 Solve it by using Translation and periodic property of sin and cos u will get the answer Question number 10 is it the question of A-Level??? i dont think so and its not the probability question so give me some time to think upon it......it related to angle -
CIE S1 Book help on Probability and Expectation & Variance Questions
is answer correct.... i dont think the number of student could be 2.5 becoz half person can never be counted so from where did thi .5 came in answer did u look at the mark scheme of same paper please check it dude -
CIE S1 Book help on Probability and Expectation & Variance Questions
sorry bro i could not get the question.... could you please paste the original copy of the question -
stats help as level
16. 8factorial /2factorial a. assume all consonants to be a single one i.e. CNCLD as X i.e. the word becomes XOUE now total arrangements = 4!/2! (since C is repeated in X) b and c are similar to this 17. Question is not so clear but i think its answer is 3 * 4C1 -
stats help as level
15. its 12factorial /(2factorial * 3factorial * 2factorial ) -
CIE S1 Book help on Probability and Expectation & Variance Questions
hahaha keep on practicing u will achieve the highest confidence to solve the problems -
CIE S1 Book help on Probability and Expectation & Variance Questions
its my pleasure dude -
CIE S1 Book help on Probability and Expectation & Variance Questions
I think the process is correct so try to get it......here it is