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Physics: Post your doubts here!
Did u get how we calculated n? Formula → nλ = dsinΘ (1*10^6) * λ = 1 * sin 35 [d = 1, as it is a 1st order diffraction] So, rearranging the eqn abv, λ = (1*sin35)/(1*10^6) λ = sin 35/(1*10^6) Hope u get it! -
Reading text messages while half asleep.....is like looking into the sun.
Reading text messages while half asleep.....is like looking into the sun.- gary221
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You call it lazy...I call it selective participation.
You call it lazy...I call it selective participation.- gary221
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$19.99.....bcoz $20.00 is just too much to pay.
$19.99.....bcoz $20.00 is just too much to pay.- gary221
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My bed is a magical place...where I suddenly remember everything I was supposed to do.
My bed is a magical place...where I suddenly remember everything I was supposed to do.- gary221
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Shortest horror story ever: Computer is not able to connect to the internet.
Shortest horror story ever: Computer is not able to connect to the internet.- gary221
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Physics: Post your doubts here!
30)http://www.s-cool.co.uk/a-level/physics/diffraction/revise-it/diffraction-from-a-diffraction-grating nλ = dsinΘ Now, n = 1/(1 * 10^-6) → 1 * 10^6 Also, the angle of 70° is btw the 2 maxima so, the angle from the centre = 70/2 → 35° Applying the formula, λ = sin 35/(1 * 10^6) λ = 574 nm Ans... -
Physics: Post your doubts here!
24)http://www.s-cool.co.uk/a-level/physics/stress-and-strain/revise-it/definitions-of-stress-strain-and-youngs-modulus We know that E is inversely proportional to the area, and directly proportional to the length. Now, when we increase the length to 3L, the extension also increases 3 times → 3x... -
Physics: Post your doubts here!
8)okay, the equation we consider here is → s = 1/2 * g * t^2 When time = T, the dist = s. However when the time = 0.5 T →time^2 = (0.5 T)^2 →0.25 T So, the dist is proportional to the square of time. Thus, when the time reduces to half its original value, dist reduces to 1/4th its original... -
I'm capable of doing amazing things to make the world a better place. Tomorrow, though.
I'm capable of doing amazing things to make the world a better place. Tomorrow, though.- gary221
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Physics: Post your doubts here!
http://www.s-cool.co.uk/a-level/physics/moments-couples-and-equilibrium/remember-it/s-cool-revision-summary Torque = force acting perpendicular to an object * horizontal dist btw the 2 forces. Now the force acting on the beam is at an angle of 60° → 30° from the normal. Now we have to find the... -
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Physics: Post your doubts here!
26) As shown in the fig, at time = 18 s, phase diff btw the 2 waves = 180° or π. 1 wavelength = 360° So, 1/8 of a wavelength = 360°/8 → 45°. Phase diff = 180° at 18 s. So, phase diff = 45° at x. x = (18 * 45)/180 x = 4.5 s Ans = B Hope u get it! All credit to Nibz. -
Physics: Post your doubts here!
16) As i already said, work done = amount of energy gained. So, since the K.E. of the vehicle = 4.5 * 10^5 J and we know that work done = Fs. So, Fs = 4.5 * 10^5 s = (4.5 * 10^5)/6000 s = 75 m. Ignore the mass, thts just to confuse u. Hope u gt it! All credit to Nibz. -
Physics: Post your doubts here!
15) When the force = F, and distance = s, work done = Fs. Since work done = K.E. gain → Fs = 8-4 = 4J Fs = 4J So, when force = 2F, and distance = 2s, work done = 2F * 2s →4Fs. Since Fs = 4J, 4Fs = 4 * 4 = 16 J. So gain in K.E. = 16 J. And since the kinetic energy already equals 4 J....the new... -
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hahahah...nahi..i was typing a VERY long reply. convo mein nahi, walls par sota hoon...:p
hahahah...nahi..i was typing a VERY long reply. convo mein nahi, walls par sota hoon...:p- gary221
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aaaaannnnnd..the minion's back.. our minion..the cute n grumpy one... \o/(y)
aaaaannnnnd..the minion's back.. our minion..the cute n grumpy one... \o/(y)- gary221
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thnx ki to baat hi nahi... nytime... :p
thnx ki to baat hi nahi... nytime... :p- gary221
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