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Search results
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TRUTH OR DARE ;):P
Pick any 3 online members to play t/d :P- Thought blocker
- Post #15,734
- Forum: Games and Fun Stuff
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TRUTH OR DARE ;):P
To not complete dare. :LOL:- Thought blocker
- Post #15,730
- Forum: Games and Fun Stuff
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TRUTH OR DARE ;):P
Put your pic as a dp. :LOL: You got 5 mins.- Thought blocker
- Post #15,726
- Forum: Games and Fun Stuff
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Mathematics: Post your doubts here!
Thats what is at last. :)- Thought blocker
- Post #13,695
- Forum: A-Levels
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Mathematics: Post your doubts here!
There is surely a mistake in the question. Wait for er- Thought blocker
- Post #13,692
- Forum: A-Levels
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Mathematics: Post your doubts here!
I got it wrong in examination. :LOL:- Thought blocker
- Post #13,690
- Forum: A-Levels
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Biology; Chemistry; Physics: Post your doubts here!
jj1234 do you agree?- Thought blocker
- Post #19,822
- Forum: O-Levels / GCSEs / IGCSE
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Mathematics: Post your doubts here!
I must say, this was the trickiest question in this year. :)- Thought blocker
- Post #13,688
- Forum: A-Levels
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Mathematics: Post your doubts here!
f(x) and g(x) ARE related to each other by the function gf(x). Solving (iii): (2x+3)^2 - 6(2x+3) = 4x^2 - 9 ≤ 16 = x^2 ≤ 25/4 x ≤ +/- 25/4 => x ≤ +25/4 or x≤-25/4 The value of x must satisfy both the domains of g(x) and f(x) Domain of g(x) is x must be less than or equal to 3, both +25/4...- Thought blocker
- Post #13,687
- Forum: A-Levels
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Mathematics: Post your doubts here!
- Thought blocker
- Post #13,685
- Forum: A-Levels
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