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  1. TheJDOG

    Physics: Post your doubts here!

    Hey, the fundamental charge ( elementary charge) is the multiple of this set of charges of oil. And thus, the elementary charge (1.6 x10^-19 C) is a multiple of the differences of these oil charges. Subtract the first two for example, 6.4x10^ -19 - 3.2x10^-19 = 3.2 x10^-19 C This difference is...
  2. TheJDOG

    Mathematics A level A-2 paper 3 complete notes 9709

    Awesome notes! I thank you for it, I read it all :) perfect, clear and thorough. Thanks again :)
  3. TheJDOG

    Mathematics: Post your doubts here!

    If you're not given the initial x when doing iteration, you start with the middle x, here x is between 0 and pie, so 0.5pie
  4. TheJDOG

    Physics: Post your doubts here!

    No bro I understand what you're trying to say but we can use h Planck's constant because we know it, and it's given in the formula sheet h= 6.63 x 10^-34 Js In part (ii) we're asked to find a value for it using Fig 7.1 and our equation. we cool?
  5. TheJDOG

    Mathematics: Post your doubts here!

    8) I had to squeeze it in a bit xD I also think my sketch is bad.
  6. TheJDOG

    Mathematics: Post your doubts here!

    5(i) I hope its clear Ill do 8 and 10(ii) for you later :)
  7. TheJDOG

    Physics: Post your doubts here!

    In this question were asked to calculate phi the work function energy using the eqaution we wrote in (i) and Fig 7.1 The maximum kinetic energy of an emitted photoelectron is Emax= hc/lambda - phi Now go back to Fig 7.1 and pick any point on the line I'll pick (1.5 x 10^-19,2.7x10^6) h the...
  8. TheJDOG

    Mathematics: Post your doubts here!

    Are you sure the ms says 0.1 m/s? Which paper is this?
  9. TheJDOG

    Mathematics: Post your doubts here!

    Here you go
  10. TheJDOG

    Mathematics: Post your doubts here!

    Let's get weight of B shall we? First off, extend the arrow of the 18 N force on B, you will see that its angle between it and the horizontal is also 30! We know B is in equilibrium also, so take axis directly on the smooth plane. Notice no friction here it's smooth. R(->) resolve on x axis...
  11. TheJDOG

    Physics, Chemistry and Biology Revision Guides [ UPDATED ]

    Awesome work Areeb :) I'm looking forward to reading your Physics A2 revision part, so I make sure I'm not missing out on anything.
  12. TheJDOG

    Mathematics: Post your doubts here!

    June or October?
  13. TheJDOG

    Physics: Post your doubts here!

    O/n 11 p43 q7 bii 2 We need a value for plancks constant, we have to find the gradient of the graph fig. 7.1. I will take these two points on the graph (1.3x10^-19,2.6x10^6) and (3.7x10^-19,3.8x10^6) Gradient = y2-y1/x2-x1= (3.8-2.6)x10^6/(3.7-1.3)x10^-19= 5x10^24 But we know that the...
  14. TheJDOG

    Physics: Post your doubts here!

    Hello zain, o/n 11 p43 q7 bii 2 Cannot find this question m/j 12 p42 q1 cii c) ii) First off, were told that the radius of the orbit of the moon increases by 4 cm each year. We need the energy change in one year We also know that Energy change= m.Change in phi ,where m is the mass and change...
  15. TheJDOG

    Maths Mechanics M1 HELP!

    I) R(->) resolve horizontally 40cos60= xcos30 X= 23.1 N II) R(->) resolve horizontally xcos30= 40cos60 + 10 New X = 34.64 N R(^) Resolve vertically 40sin60 + 34.64sin30 + R = 150 Weight is 150 R= 98.01 But f= uR 10 = u x 98.01 u = 0.102
  16. TheJDOG

    Maths Mechanics M1 HELP!

    You cannot get the correct answer from resolving vertically because there's also the normal contact force R which you don't know
  17. TheJDOG

    Mathematics: Post your doubts here!

    Hello Paresh. Q6) I)First off, were told that perimeter of shade= 1/2 circle circumference Find radius of shade by dropping down a perpendicular so you get this in terms of r and x. Also theta here will be 2x. Radius of shade we do cosx= Adj/r , hence adj = rcosx and so side AB= 2rcosx Also...
  18. TheJDOG

    Physics: Post your doubts here!

    Ok bro, just solved this for you. Read carefully 9a)i) they want the mean activity of the sample, the mean activity is change in N/change in t Where N is the nuclei at time t. ii) probability of decay of a nucleus is the change in N / N b) Given : cobalt-60 source half life: 5.27 years...
  19. TheJDOG

    Physics: Post your doubts here!

    Hey you all! How's everyone lately? I'm back here :D really missed helping people in physics. Physics <3
  20. TheJDOG

    Physics 12 GT

    Nah, don't worry! Go enjoy summer now! Also, am sure you did great in the other papers, so don't worry :) Also, follow what your own signature says, the solution is always with God :)
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