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Chemistry: Post your doubts here!
for 21, the ans is B, bcoz, since the 2 alcohols r primary, they will both react with potassium manganate ie get oxidised, this rules out A.. since both the alcohols have only 1 OH grp, the OH grp will get replaced by Na & Cl, thus substitution reaction same for both alcohols, this rules out C n... -
Chemistry: Post your doubts here!
for 15, d ans is A, bcoz, the 1st test proves tht u hv a halide which is nt fluoride since u gt a ppt. the 2nd test is to define which halide is present, since the ppt dissolves in excess NH3, this shows that d halide present is Chloride...n since A is the only option with chloride the ans is A... -
Chemistry: Post your doubts here!
For 12, the ans is A, bcoz whn u acidify the pool, the OH ions will react wth the H ions in the acid to neutralise it...this will result in a decrease in the conc of OH ions, n following Le Chatliers principle, d equilibrium will shift 2 d products side, more products ie HOCl will b fromd... -
Chemistry: Post your doubts here!
whn grp 2 nitrates r heated they form a metal oxide, nitrogen dioxide n oxygen...tht is fixed for all grp 2 metals...then u hv 2 balance d equation.. ie 2 Mg(NO3)2 = 2 MgO + 4 NO2 + O2 try this :http://www.chemguide.co.uk/inorganic/group2/thermstab.html hope i helped...:D -
~~jokes?? in here?? really??
- gary221
- Post #3,183
- Forum: Games and Fun Stuff
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Chemistry: Post your doubts here!
hey does sum1 know how 2 solv this?? -
Chemistry: Post your doubts here!
remember d formula, Kc = Molar conc of product/ molar conc of reactants (both raised to the power of thr stoichiometric coefficient) Initial conc of H2 n I2 is 0.2 n 0.15 resp. Inititl conc of HI = 0 Final conc of HI = (0.26/2) as thr r 2 moles of HI formed So. final conc of H2 = 0.20-0.13... -
Chemistry: Post your doubts here!
See, u only hv 2 luk at nitrogen on both sides... on LHS, let d oxidation no of N be x, so x + 3(+1) = 0 {since thr r 3 hydrogen, n d overall chrge of the molecule is 0} so, d oxidation no. of N is -3 On RHS, let d oxidation no of N be x, so x +(-2) = 0 {oidation no of oxygen is -2) so. N= +2... -
Chemistry: Post your doubts here!
@amatyasrizan, if sum1 helped u out...its btr 2 press the like button...:D -
Chemistry: Post your doubts here!
as far as i can see, increasing d temp, affects d energy.. not d no. of collisions, at least nt directly...i think d ans shud be D -
Chemistry: Post your doubts here!
d ques is nt related 2 d formation of nitric acid, u hv 2 calculate d oxidation no. of nitrogen in all d cases... whr d greatesr chnge in nitrogen happens ie in A ( changes frm -3 to +2) is d correct ans.. hope i helped.. -
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~~jokes?? in here?? really??
- gary221
- Post #3,178
- Forum: Games and Fun Stuff
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Chemistry: Post your doubts here!
Hey can sum1 explain why the ans for this is c