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Mathematics: Post your doubts here!
All people sketch a graph! Well here is video tutorial :¬ http://www.examsolutions.net/maths-revision/syllabuses/CIE/period-1/P1/module.php Ch : 2 :)- Thought blocker
- Post #13,495
- Forum: A-Levels
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A-2 Complete Guide for Pre-Medical/Pre-Engineering Students
All the best. :thumbsup: Liked it. ;)- Thought blocker
- Post #3
- Forum: A-Levels
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XPC FUN COUNCIL-3 :D
And you expect a vote. :P Aamir Khan! :P- Thought blocker
- Post #284
- Forum: Off Topic
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XPC FUN COUNCIL-3 :D
Miss perfect. Do you know who is Mr.Perfectionist? :D- Thought blocker
- Post #282
- Forum: Off Topic
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Mathematics: Post your doubts here!
I will twist it to : (sin^3x+cos^3x)/(sinx+cosx) = 1-sinxcosx. Its the same question, just a minor twist, do it yourself the original question, here it is :¬ => (sin^3x+cos^3x)/(sinx+cosx) [Just use the a^3+b^3 formula] => [(sinx+cosx)(sin^2x-sinx.cosx+cos^2x)] / (sinx+cosx) [The sinx+cosx...- Thought blocker
- Post #13,493
- Forum: A-Levels
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XPC FUN COUNCIL-3 :D
You didn't mentioned that in your rules. :/- Thought blocker
- Post #280
- Forum: Off Topic