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Physics: Post your doubts here!
I did it like this, on the first sight :P- Thought blocker
- Post #10,683
- Forum: A-Levels
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Physics: Post your doubts here!
10) Consider barrel : Use F = ma That is mg - T = ma (T = tension): 120g - T = 120a Make T the subject of formula so, later we can equate it in other equation or you can solve it by simultaneous equation method also. But I personally go for Equate so, T = 120g - 120a Consider stake : Again...- Thought blocker
- Post #10,682
- Forum: A-Levels
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Physics: Post your doubts here!
0.7 m ----> 1.1V 0.9m ----> ? ? = 1.4V = D- Thought blocker
- Post #10,681
- Forum: A-Levels
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Physics: Post your doubts here!
Find lost volts(V) = E - Ir so V = 12 - (0.8)(2) = 10.4V Now P = I x V = 0.8 x 10.4 = 8.3W = A- Thought blocker
- Post #10,680
- Forum: A-Levels
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Physics: Post your doubts here!
I am solving everyones doubt line by line, wait... :) Or try yourself, its damn easy.. :)- Thought blocker
- Post #10,679
- Forum: A-Levels
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Physics: Post your doubts here!
5) We know S = d / t = 40 / 2.5 = 16 m/s Uncertainty in speed = (uncertainty in distance + uncertainty in time) x speed --------"--------------- = ( (0.1/40 ) + (0.05/2.5) ) x 16 = 0.36 ≈ 0.4 (1dp) = C 12) Consider barrel : Use F = ma That is mg - T = ma (T = tension): 120g - T = 120a Make T...- Thought blocker
- Post #10,678
- Forum: A-Levels
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Physics: Post your doubts here!
Let's do the math behind this - suppose the distance traveled with both speeds is denoted by "s". Suppose the time taken at 600 kmph = t(1). Then, since Speed = Distance/Time, we can write 600 = s/t(1) So that t(1) = s/600 Similarly, let's do the same for the other speed. The distance...- Thought blocker
- Post #10,676
- Forum: A-Levels
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Physics: Post your doubts here!
Okay, we know V = 340 and f = 500 so take out λ = V / f = 0.68 m We know that one wavelength means 360 ⁰ i.e, 2π so now use the cross multiplication method 0.68 --- > 2π 0.17 -----> ? ? = 90 i.e, π/2- Thought blocker
- Post #10,675
- Forum: A-Levels
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Physics: Post your doubts here!
I = kA² k=I/A² (equation 1) at other position of meter that is equation 2 : 2I=k(x²) 2I= (I/A²) * x² ( 2I * A² ) / I = x² Taking √ both the sides, x = √ 2 * A 24) I α a^2 and I α f^2. Rather than doing all the math to do this, compare the amplitude and frequency of the waves and use the...- Thought blocker
- Post #10,674
- Forum: A-Levels
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Hope so. But I know, it would never be alright. Thanks :)
Hope so. But I know, it would never be alright. Thanks :)- Thought blocker
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Physics: Post your doubts here!
25) Use dsinθ = nλ So given, θ = 45 and n = 3 so d x sin45 = 3λ ---> equation 1 We need to find highest order yes so check at which values of θ the sinθ has its maximum value, that is sin90 = 1 so we get other equation : d x sin90 = nλ ---> equation 2 Now divide Equation 1 by 2 so that d and λ...- Thought blocker
- Post #10,655
- Forum: A-Levels
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Physics: Post your doubts here!
The circuit is arranged in the same way if you see carefully, so values would be unchanged so A- Thought blocker
- Post #10,653
- Forum: A-Levels
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Physics: Post your doubts here!
w12_12 5) Simple concept, use your brain :) 19) Use Pressure = force / area and find force ( dont forget to keep basic units of area ) Then w.d = f x d = A ( distance in meter) 27) 30) Apply d*sin thetha = n*lamida d = 1/n where n is no. of line/m. Metre not millimetre. Grating's got...- Thought blocker
- Post #10,652
- Forum: A-Levels
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Physics: Post your doubts here!
s12_12 6) 1µs --> 1 cm so, each pulses are in 2 cm so 2cm ---> 2µs 8) Use S = ut + 0.5 at^2 for distance X : S = 0t1 + 0.5 at1^2 Here S = x so x = 0.5 x a x t1^2 ---> equation 1 Now distance x + h so s = 0t2 + 0.5 at2^2 Here S = x + h so x = 0.5 x a x t2^2 - h --> equation 2 So As x...- Thought blocker
- Post #10,651
- Forum: A-Levels
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