-
We need your support!
We are currently struggling to cover the operational costs of Xtremepapers, as a result we might have to shut this website down. Please donate if we have helped you and help make a difference in other students' lives!
Click here to Donate Now (View Announcement)
Search results
-
-
As physics p1 MCQS YEARLY ONLY.
Solve Q35 and I am feeling this are some hard. Hope you get me. Thanks.- Thought blocker
- Post #818
- Forum: A-Levels
-
As physics p1 MCQS YEARLY ONLY.
8) First calculate accn from first information V^(2) - U^(2) = 2as 36 - 64 = 14a a = -2 m/s^(2) Now find s from same equation V^(2) - U^(2) = 2as 0^(2) - 6^(2) = 2(-2)s s = 9m 15) viscous force - Force that act on a body moving through a fluid that are caused by the resistance of the fluid...- Thought blocker
- Post #817
- Forum: A-Levels
-
-
Physics: Post your doubts here!
4) 10 ms = 1cm , total 8.5 waves in 6 cm, so if 10 ms = 1 cm so 6 cm = 60 ms and 60 ms = 0.006 s So in 0.06 s there are 8.5 waves. so in 1 wave what is the value of time, that will be 0.00706 s As you know f = 1 / T, f = 1 / 0.00706 = 141 that is 140 approx so B 16) The Efficiency = (Useful...- Thought blocker
- Post #10,238
- Forum: A-Levels
-
-
-
-
-
-
-
Physics: Post your doubts here!
Well, gtg here is both answers... 9702_s11_qp_12 17) Perpendicular =80/2 =40 mm Find the angle. Sin Θ = 40/50= 53.1° As there are two tensions both equal, so Force = 2(cos 53.1 x 4) = 4.8 N 9702_s11_qp_11 17) From 1st info, calculate the mass - m = K.E / 0.5*V^(2) = 30 kg Now from second info...- Thought blocker
- Post #10,235
- Forum: A-Levels
-
-
-
-
-
-
Don't force her, she'll decide what to do :) Please. :)
Don't force her, she'll decide what to do :) Please. :)- Thought blocker
- Profile post comment
-
-